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3 years ago

9. Let f(x) = 4x + 7 and g(x) = 3x - 5. Find.(g×f)(-4) Pick one

Mathematics

1 answer:

gladu [14]3 years ago

5 0

Answer:

-32

Step-by-step explanation:plug f(x) equation in the x in the g equation so you have 3(4x+7)-5

then distribute the 3 and you end up with 12x+21-5

combine like terms

12x+16

plug in negative four and solve

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-15x + 5 = -10x + 25 solve for x

tatuchka [14]

Answer:

Move all terms containing x to the left side of the equation.

−5x+5=25

Move all terms not containing x to the right side of the equation.

−5x=20

Divide each term by −5 and simplify.

x=−4

Step-by-step explanation:

6 0

3 years ago

Rewrite as a simplefied fraction

9966 [12]

Answer:
79/25

Work:

Firstly, you have to change the decimal portion of 3.16 (0.16) into a fraction, then you simplify it by a common factor, which is 4. You then convert your whole number, which is 3, into an improper fraction by multiplying it by 25 and making that the numerator, 25 being the denominator of the fraction. Then, you add the two fractions and voila! You have a simplified fraction!

0.16 = 16/100

16/100 = 4/25

3 x 25 = 75

75/25 + 4/25 = 79/25

3 0

3 years ago

the perimeter of a rectangle brownie pan is 50 Inches. the lenght of the pan is 5 less than twice the width. write a system of e

Serga [27]

Answer: The system of equation is,

2 ( x + y ) = 50

x = 2 y - 5

Step-by-step explanation:

Let x represents the length of the rectangular brownie and y represents the width of the rectangular brownie.

Thus, the perimeter of the brownie = 2 ( x + y )

But, According to the question,

Perimeter of the brownie = 50,

2 ( x + y ) = 50

The length of the brownie is 5 less than twice the width,

That is, x = 2 y - 5

Thus, the required system of equation is,

2 ( x + y ) = 50 , x = 2 y - 5

6 0

3 years ago

Lily made a scale drawing of a house and its lot. The scale she used was 7 inches = 3 feet. What is the scale factor of the draw

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

7/3 inches = 1 ft

3 0

2 years ago

mr.browns salary is 32,000 and imcreases by $300 each year, write a sequence showing the salary for the first five years when wi

chubhunter [2.5K]

Hello!

We have the following data:

a1 (first term or first year salary) = 32000

r (ratio or annual increase) = 300

n (number of terms or each year worked)

We apply the data in the Formula of the General Term of an Arithmetic Progression, to find in sequence the salary increases until it exceeds 34700, let us see:

formula:

$a_n = a_1 + (n-1)*r$

* second year salary

$a_2 = a_1 + (2-1)*300$

$a_2 = 32000 + 1*300$

$a_2 = 32000 + 300$

$\boxed{a_2 = 32300}$

* third year salary

$a_3 = a_1 + (3-1)*300$

$a_3 = 32000 + 2*300$

$a_3 = 32000 + 600$

$\boxed{a_3 = 32600}$

* fourth year salary

$a_4 = a_1 + (4-1)*300$

$a_4 = 32000 + 3*300$

$a_4 = 32000 + 900$

$\boxed{a_4 = 32900}$

* fifth year salary

$a_5 = a_1 + (5-1)*300$

$a_5 = 32000 + 4*300$

$a_5 = 32000 + 1200$

$\boxed{a_5 = 33200}$

We note that after the first five years, Mr. Browns' salary has not yet surpassed 34700, let's see when he will exceed the value:

* sixth year salary

$a_6 = a_1 + (6-1)*300$

$a_6 = 32000 + 5*300$

$a_6 = 32000 + 1500$

$\boxed{a_6 = 33500}$

* seventh year salary

$a_7 = a_1 + (7-1)*300$

$a_7 = 32000 + 6*300$

$a_7 = 32000 + 1800$

$\boxed{a_7 = 33800}$

* eighth year salary

$a_8 = a_1 + (8-1)*300$

$a_8 = 32000 + 7*300$

$a_8 = 32000 + 2100$

$\boxed{a_8 = 34100}$

* ninth year salary

$a_9 = a_1 + (9-1)*300$

$a_9 = 32000 + 8*300$

$a_9 = 32000 + 2400$

$\boxed{a_9 = 34400}$

* tenth year salary

$a_{10} = a_1 + (10-1)*300$

$a_{10} = 32000 + 9*300$

$a_{10} = 32000 + 2700$

$\boxed{a_{10} = 34700}$

we note that in the tenth year of salary the value equals but has not yet exceeded the stipulated value, only in the eleventh year will such value be surpassed, let us see:

* eleventh year salary

$a_{11} = a_1 + (11-1)*300$