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4 years ago

15

On the distant plant, Mathology, a sports area covers 7400 yodels2. How many square deckles would this be if 1 deckle = 75.9 yod

els?

1 answer:

STatiana [176]4 years ago

8 0

Answer:

It would be <u>97.50</u> square deckles.

Step-by-step explanation:

Given:

On the distant plant, Mathology, a sports area covers 7400 yodels².

1 deckle = 75.9 yodels.

Now, to get the square deckles.

As given, 1 deckle = 75.9 yodels.

So, to get the square deckles by using conversion factor:

<em>75.9 yodels = 1 deckle.</em>

7400 yodels² = $7400\div 75.9$

= $97.50\ deckels ^2.$

Therefore, it would be 97.50 square deckles.

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Please help with this question, thank you

Semmy [17]

Remark
The key step is just to subtract 5 from both sides. The pointed of the inequality still points away from the variable and towards the number. As long as that remains true, the correct answer can be found.

Solution
2.7 ≤ b + 5 Subtract 5 from both sides.
2.7 - 5 ≤ b
- 2.3 ≤ b Write with the variable on the left.
b ≥ - 2.3 <<<< answer

6 0

3 years ago

Read 2 more answers

Anne, Barry, and Cathy enter a coffee shop. Anne orders two coffees, one juice, and two doughnuts and pays $7.50. Barry orders o

Evgesh-ka [11]

Answer:

Coffee = $2.00

Juice = $1.50

Doughnut = $1.00

Step-by-step explanation:

Given

Let:

$c = coffee\\ j= juice\\ d = doughnut$

So, we have:

Anna

$2c + j + 2d = 7.50$

Barry

$c + 3d = 5.00$

Cathy

$3c + j + 4d = 11.50$

Required

The price of each

We have:

$2c + j + 2d = 7.50$

$c + 3d = 5.00$

$3c + j + 4d = 11.50$

Make c the subject in: $c + 3d = 5.00$

$c = 5.00 - 3d$

Substitute $c = 5.00 - 3d$ in $2c + j + 2d = 7.50$ and $3c + j + 4d = 11.50$

$2c + j + 2d = 7.50$

$2[5.00 - 3d] + j + 2d = 7.50$

$10.00 - 6d+ j + 2d = 7.50$

Make j the subject

$j = 7.50 - 10.0 +6d - 2d$

$j = -2.50 +4d$

$3c + j + 4d = 11.50$

$3[5.00 - 3d] + j + 4d = 11.50$

$15.00 - 9d + j + 4d = 11.50$

Make j the subject

$j = 11.50 - 15.00 + 9d -4d$

$j = -3.50 + 5d$

So, we have:

$j = -3.50 + 5d$ and $j = -2.50 +4d$

Equate both values of j

$-3.50 + 5d = -2.50 + 4d$

Collect like terms

$5d - 4d = 3.50 -2.50$

$d = 1.00$

Substitute $d = 1.00$ in $j = -3.50 + 5d$

$j = -3.50 + 5d$

$j = -3.50 + 5 * 1.00$

$j = -3.50 + 5.00$

$j = 1.50$

To solve for c, we substitute $d = 1.00$ in $c + 3d = 5.00$

$c + 3 * 1.00 =5.00$

$c + 3.00 =5.00$

Solve for c

$c =- 3.00 +5.00$

$c =2.00$

7 0

3 years ago

-5, 20, -80, 320, ... is a geometric sequence a. Find the common ratio, b. Write its recursive rule c. Write its explicit rule.W

mario62 [17]

a.

In order to find the common ratio, we just need to divide a term by the term that comes before it.

So using the terms 20 and -5, we have:

$\text{ratio}=\frac{20}{-5}=-4$

b.

The recursive rule can be found with the formula:

$a_n=a_{n-1}\cdot q$

Where an is the nth term and q is the ratio. So we have:

$a_n=a_{n-1}\cdot(-4)$

c.

The explicit rule can be written as:

$a_n=a_1\cdot q^{n-1}$

Where an is the nth term, a1 is the first term and q is the ratio. So:

$a_n=-5\cdot(-4)^{n-1}$

5 0

1 year ago

Which of these expressions CANNOT be simplified by combining like terms?

densk [106]

$5ab^{3} +7-3a^{2} b ^{2} +a^{3}b+10$ can be simplified to by adding the 7 and 10 to get $a^{3}b-3a^{2} b ^{2}+ 5ab^{3} + 17$ .

$5ab^{3}+3a^{2}b^{2}+a^{3}b -10$ cannot be simplified any more by combining like terms.

By distributing the 2b into the parentheses, you can simplify the expression:
$5ab^{3}+2b(3ab^{2})+a^{3}b-10\\
5ab^{3}+6ab^{3}+a^{3}b-10\\
11ab^{3}+a^{3}b-10$

Here you can just add:
$5a^{3}b^{3}+3a^{2}b^{2}+a^{3}b^{3}-10ab\\
6a^{3}b^{3}+3a^{2}b^{2}-10ab$

Thus, the only expression that cannot simplify any more using adding like terms is the second, $5ab^{3}+3a^{2}b^{2}+a^{3}b -10$ .

3 0

3 years ago

Read 2 more answers

Example of how is the quadratic equation used in nursing?

Mumz [18]

Answer:

Nurses use this to calculate dosage needed for patients, calculating drip rates and conversion between systems.

Step-by-step explanation:

3 0

3 years ago