Answer:
9/11
Step-by-step explanation:
Well we know there are 55 students in total and only 45 of them can either play a string or brass instrument.
So 45/55 is 9/11
Thus probably is 9/11 of a randomly selected student who plays either a string or brass.
Answer:
276
Step-by-step explanation:
60 feet plus 3 is 63, 63 times 2 is 126, 126 +150 is 276
Answer:
B: The mean study time of students in Class B is less than students in Class A.
Step-by-step explanation:
To find out why answer B is the right answer, I will give you facts from each option.
Option A is false. <em>The mean study time in Class A is 4.8. Meanwhile in Class B it is 4. For Class A, sum up the 20 study times which is 96 and divide them by 20, you will get 4.8 hours of mean study time. For Class B, the sum of the 20 study times is 80, which divided by 20 will be 4.
</em>
Option B is True. <em>See previous explanation.
</em>
Option C is False. <em>The median study time in Class B is 4. The median study time in Class A is 4.8,
</em>
Option D is False. <em>The range in Class A is from 2 to 8. The range in Class B is from 2 to 7.
</em>
Option E is False: <em>The mean and median study time of these classes is different.</em>
The general way to work this out is to solve the general expression for
the remaining quantity versus half-life, using logarithms. But that's not
necessary with these numbers.
Look at the numbers:
-- 3 mg is 1/4 of 12 mg.
-- 1/4 is the product of (1/2) x (1/2).
-- So the 3 mg is what's left of 12 mg after 2 half-lives.
The 26 minutes must be two half-lives.
-- The half-life of that substance is 26/2 = <em>13 minutes</em>.
Go Maggie !
