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CaHeK987 [17]
3 years ago
12

Calculate the relativistic speed of a particle at a time 6 s after it star t = 0 s . The mass of the particle is 6 × 10-2 kg and

the force acting is! (a) 0.0411o (b) 0.0350c (c) 0.0366c (d) 0.0390c
Physics
1 answer:
Mars2501 [29]3 years ago
6 0

Answer:

The relativistic speed of a particle is 0.0333\times10^{-5}c

Explanation:

Given that,

Time = 6 sec

Force = 1

Mass of the particle m=6\times10^{-2}\ kg

We need to calculate the acceleration

Using formula of acceleration

a = \dfrac{F}{m}

Put the value into the formula

a=\dfrac{1}{6\times10^{-2}}

a=16.67\ m/s^2

We need to calculate the velocity after 6 sec

Using equation of motion

v = u+at

Put the value

v=0+16.67\times6

v=100\ m/s

The velocity in term of c

v=\dfrac{100c}{3\times10^{8}}

v=3.333\times10^{-7}c

v=0.0333\times10^{-5}c

Hence, The relativistic speed of a particle is 0.0333\times10^{-5}c

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iris [78.8K]

Answer:

The longest wavelength of radiation that passesses the necessary energy for breaking the Cl- Cl bond (in Cl2) is approximately 494.2 nm, which corresponds to the visible spectrum.

Explanation:

In order to answer this question we need to recall that the energy of a photon is given by:

E = hc/lambda,   where

E = energy

h = Planck's constant

c = speed of light in vacuum

lambda = associated photon wavelength

In order to perform the calculations, first we need to change the units of 242kJ/mol to J. For doing this, we to divide by Avogadro's number and multiply by a 1000:

242kJ/mol = (242kJ/mol)*(1mol/6.022x10^23 particles)*(1000J/1kJ)= 4.0186x10^-19 J

Now, we simply solve for lambda and substitute the appropriate values in the energy equation:

lambda = hc/E = (6.626x10^-34 J s)*(3x10^8 m/s)/(4.0186x10^-19 J) = (1.986x10^-25 J m)/(4.0186x10^-19 J) = 4.942x10^-7 m = 494.2x10^-9 m = 494.2 nm

Therefore, the wavelength for a photon to break the Cl-Cl bond in a Cl2 molecule should be 494.2 nm at most, which corresponds to the visible spectrum (The visible spectrum includes wavelengths between 400 nm and 750 nm).

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The force of the car engine.

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