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White raven [17]
2 years ago
8

A 0.1 kg toy contains a compressed spring. when the spring is released the toy fly 0.45 m upwards from ground level before falli

ng back down to the ground. what is the speed of the toy when it hits the ground.
Physics
1 answer:
trapecia [35]2 years ago
7 0

The speed of the toy when it hits the ground is 2.97 m/s.

The given parameters;

  • mass of the toy, m = 0.1 kg
  • the maximum height reached by the, h = 0.45 m

The speed of the toy before it hits the ground will be maximum. Apply the principle of conservation of mechanical energy to determine the maximum speed of the toy.

P.E = K.E

mgh_{max} = \frac{1}{2} mv_{max}^2\\\\gh_{max} = \frac{1}{2} v_{max}^2\\\\v_{max}^2= 2gh_{max}\\\\v_{max} = \sqrt{2gh_{max}}

Substitute the given values and solve the speed;

v_{max} = \sqrt{2\times 9.8 \times 0.45} \\\\v_{max} = 2.97 \ m/s

Thus, the speed of the toy when it hits the ground is 2.97 m/s.

Learn more here: brainly.com/question/7562874

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Force the glove exerts on the ball

Explanation:

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3 years ago
A golf ball is dropped from rest from a height of 9.50m. It hits the pavement, then bounces back up, rising just 5.70m before fa
marta [7]

Answer:

Explanation:

Given

height from which ball is dropped h_1=9.5\ m

and it rises to a height of h_2=5.7\ m

A person caught the ball in mid-way i.e. at a height of h_0=1.2\ m from pavement

time taken to reach the bottom is given by

y=ut+\frac{1}{2}at^2

where  y=displacement

u=initial velocity

a=acceleration

t=time

here initial velocity is zero i.e.

h_1=0+\frac{1}{2}gt_1^2

t_1=\sqrt{\frac{2h_1}{g}}

Similarly to reach of  height h_2 time taken is t_2

t_2=\sqrt{\frac{2h_2}{g}}

The ball is caught in mid-way i.e. ball travel a distance of h_3=5.7-1.2=4.5\ m

time taken is t_3=\sqrt{\frac{2h_3}{g}}

total time taken t=t_1+t_2+t_3

t=\sqrt{\frac{2h_1}{g}}+\sqrt{\frac{2h_2}{g}}+\sqrt{\frac{2h_3}{g}}

t=\sqrt{\frac{2\cdot 9.5}{9.8}}+\sqrt{\frac{2\cdot 5.7}{9.8}}+\sqrt{\frac{2\cdot 4.5}{9.8}}

t=3.429\ s

total time =3.429 s

4 0
3 years ago
An experiment is designed to test the relationship between the initial height of a basketball before it is dropped to the height
Virty [35]

Answer:

A. The starting height of the ball

Explanation:

When we talk about controlled variables, we refer to the variable that should be kept the same throughout the experiment. The reason why we do this, is to limit anything else that is not being tested, that may affect the results of the experiment.

In the scenario given, the experiment is to see the relationship between the <u>initial height of a basketball</u> and the <u>height of its rebound bounce. </u>

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