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avanturin [10]
3 years ago
9

How can a karate expert break a concrete block

Physics
1 answer:
FinnZ [79.3K]3 years ago
8 0

Many ways, but some of the most famous are kicks (side, back, front, snap) or a smash.

Hope it helped! :)

You might be interested in
A girl playing tug-of-war with her dog pulls the dog a distance of 8.0m by exerting a force at an angle of 18° with the horizont
AnnZ [28]

Answer:

25 N

Explanation:

Work is a product of force and perpendicular distance moved.

W=Fd where F is force exerted and d is perpendicular distance.

However, for this case, the distance is inclined hence resolving it to perpendicular so that it be along x-axis we have distance as dcos\theta

Therefore, W=Fdcos\theta

Making F the subject of the formula then

F=\frac {W}{dcos\theta} where \theta is the angle of inclination. Substituting 190 J for W then 18 degrees for \theta and 8 m for d then

F=\frac {190}{8cos18^{\circ}}\approx 25N

3 0
2 years ago
What's the velocity for each trial? <br> And what's the average velocity?
adelina 88 [10]
Since each time trial is the same the average will be the direct answer, and the formula for velocity is distance divided by time, therefore it will come out to, 1.92307692. Whatever your teacher what the rounding process to be will vary but the straight up answer is there.
5 0
3 years ago
PLEASE HELP ME IM ON A TIMER
garri49 [273]

Answer:

Displacement: 6.71 m, Direction: 63.4 degrees north of east

Explanation:

In the attached image we can aprecciate each one of the movements of the parade. Let's say that the parade started from the origin (point (0,0)) then it moves to the east 4 blocks it means now the parade is located at point (4,0).

Then the parade went to the south three blocks, so it moves to the coordinate (4,-3). After this the parade went to the west one block so the new coordinate point is (3, -3).

And finally the movement of the 0 parade was 9 blocks to the north. It means the final point is now (0,9) - (3,-3) = (3,6)

And the displacement will be defined by the folliwing vector operation:

A (0,0) = oi + 0j\\F (3,6) = 3i + 6 j\\Displacement vector = (3-0)i + (6-0)j = 3i + 6j

We know that the magnitude of the displacement vector is defined by the phytagoras theorem

Displacement = \sqrt{(3)^2+ (6)^2} \\Displacement = 6.70

And the angle will be defined by:

tan(beta)=3/6

beta = tan^-1(6/3)

beta = 63.43°

5 0
3 years ago
If 35 J of work was performed in 70 seconds, how much power was used to do this task?
Irina18 [472]
P = w \times delta \: T
P = Power
W = Work
Delta T = Change of Time

So:
P = 35 Joules
Delta T = 70 secs
W = ?

P = 35 \div 70 \\ P = 0.5 \: watts

* Joule/Sec = Watt

Answer: The power used to do this task was 0.5 Watts.
5 0
2 years ago
A negatively charged rod of finite length carries charge with a uniform charge per unit length. Sketch the electric field lines
stiv31 [10]

Answer:

In the case of a negatively charged rod, the field lines points radially towards the rod.

Explanation:

Field lines pointing towards the negatively charged rod are used to represent the nature of an electric field. Field lines always points in a direction, i.e If the charge is positive, field lines points radially away from the rod and if the charge is negative the field lines points radially towards the rod. So in the case of a negatively charged rod, the field lines points radially towards the rod.

3 0
3 years ago
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