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algol [13]
3 years ago
13

Simplify 8^-5 over 8^-3

Mathematics
2 answers:
Alex3 years ago
7 0

Answer:

64-5 divided by 64-3 is 59 divided by 61. 59

8 squared is equal to 64.                           -----

                                                                     61

Step-by-step explanation:

trasher [3.6K]3 years ago
7 0

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{8^{-5}}{8^{-3}}\implies \cfrac{1}{8^{-3}\cdot 8^5}\implies \cfrac{1}{8^{-3+5}}\implies \cfrac{1}{8^2}\implies \cfrac{1}{64}

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Does the point(1, 8)satisfy the inequality y ≥ 6x + 2 ?
nalin [4]

Answer: Yes

Step-by-step explanation:

1. Substitute 1 for x

2. 6 times 1 is 6 plus 2 is 8

3.8 is equal to or greater than 8

4 0
3 years ago
The sum of two integers is 6 and the difference between the numbers is 40. Find the numbers
nevsk [136]


Set up a system of equations.

X+y=6
Y-x =40

Substitution method.

Y=6-x

(6-x)-x =40
6-2x=40
-2x=34
X= -17

Plug it back into the equation.
-17+y=6
Y=33

(-17,33) is one of the possible answers.







8 0
4 years ago
Read 2 more answers
Plz help!!!!!!!!!!!!!!!!!
Andrews [41]
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8 0
3 years ago
Simplify the expression. 6k – 1 + 6k
den301095 [7]
12k-1 is the simplified answer
5 0
3 years ago
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Solve the following system. y = x 2 - 9x + 10 and x + y + 5 = 0. Enter the solution with the smaller x value first.
pochemuha
X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5  add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)

7 0
3 years ago
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