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3 years ago

13

Simplify 8^-5 over 8^-3

2 answers:

Alex3 years ago

7 0

Answer:

64-5 divided by 64-3 is 59 divided by 61. 59

8 squared is equal to 64. -----

61

Step-by-step explanation:

trasher [3.6K]3 years ago

7 0

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{8^{-5}}{8^{-3}}\implies \cfrac{1}{8^{-3}\cdot 8^5}\implies \cfrac{1}{8^{-3+5}}\implies \cfrac{1}{8^2}\implies \cfrac{1}{64}$

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2 years ago

Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal poi

Ksivusya [100]

Given:

A line segment with initial point (–5, 3) and terminal point (1, –6).

To find:

The set of parametric equations over the interval 0 ≤ t ≤ 1 which defines the given line segment.

Solution:

Initial point is (–5, 3). So,

$x(0)=-5,y(0)=3$

Terminal point is (1, –6).

$x(1)=1,y(1)=-6$

Check which of the given set of parametric equations satisfy $x(0)=-5,y(0)=3,x(1)=1,y(1)=-6$ .

Put t=1 in each set of parametric equations.

In option A,

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So, option A is incorrect.

In option B,

$y(1)=1-6(1)=1-6=-5\neq -6$

So, option B is incorrect.

In option C,

$y(1)=3-9(1)=3-9=-6$

$x(1)=-5+6(1)=-5+6=1$

Put t=0, in this set of parametric equations.

$x(0)=-5+6(0)=-5$

$y(0)=3-9(0)=3$

So, option C is correct.

In option D,

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So, option D is incorrect.

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3 years ago

Part A: What is the value of 2x if 4x + 6 = 2x – 12?

xeze [42]

Answer:

Step-by-step explanation:

A) 4x + 6 = 2x - 12

Subtract 6 from both sides

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4x = 2x - 18

Subtract 2x form both sides

4x - 2x = 2x - 18 - 2x

2x = -18

B) 24 = 6x - 18

6x - 18 = 24

6x - 6*3 = 24

6(x - 3) = 24

Divide both sides by 6

$\frac{6(x - 3)}{6}=\frac{24}{6}\\\\$

x - 3 = 4

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3 years ago

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Answer:

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2 years ago