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algol [13]
3 years ago
13

Simplify 8^-5 over 8^-3

Mathematics
2 answers:
Alex3 years ago
7 0

Answer:

64-5 divided by 64-3 is 59 divided by 61. 59

8 squared is equal to 64.                           -----

                                                                     61

Step-by-step explanation:

trasher [3.6K]3 years ago
7 0

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{8^{-5}}{8^{-3}}\implies \cfrac{1}{8^{-3}\cdot 8^5}\implies \cfrac{1}{8^{-3+5}}\implies \cfrac{1}{8^2}\implies \cfrac{1}{64}

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Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal poi
Ksivusya [100]

Given:

A line segment with initial point (–5, 3) and terminal point (1, –6).

To find:

The set of parametric equations over the interval 0 ≤ t ≤ 1 which defines the given line segment.

Solution:

Initial point is (–5, 3). So,

x(0)=-5,y(0)=3

Terminal point is (1, –6).

x(1)=1,y(1)=-6

Check which of the given set of parametric equations satisfy x(0)=-5,y(0)=3,x(1)=1,y(1)=-6.

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In option A,

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So, option A is incorrect.

In option B,

y(1)=1-6(1)=1-6=-5\neq -6

So, option B is incorrect.

In option C,

y(1)=3-9(1)=3-9=-6

x(1)=-5+6(1)=-5+6=1

Put t=0, in this set of parametric equations.

x(0)=-5+6(0)=-5

y(0)=3-9(0)=3

So, option C is correct.

In option D,

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3 years ago
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Answer:

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Answer:

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