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erastova [34]
3 years ago
14

At a swim meet, it took Deborah 40.8 seconds to complete the 50 meter freestyle event. It took Robert 60.2 seconds to complete t

he 100 meter butterfly event. It took Emily 112.4 seconds to complete the 200 meter medley event. Who swam the fastest?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0

Answer:

Emily's speed is the greatest, therefor she is the fastest at a speed of 1.78 m/s

Step-by-step explanation:

To determine who swam the fastest we need to calculate the speed for each swimmer;

Speed=Distance/time

Deborah covered a distance of 50 meters in 40.8 seconds,

Deborah's speed=(Deborah's distance/Time)=(50/40.8)=1.23 meters per second

Robert covered a distance of 100 meters in 60.2 seconds,

Robert's speed=(Robert's distance/Time)=(100/60.2)=1.66 meters per second

Emily covered a distance of 200 meters in 112.4 seconds,

Emily's speed=(Emily's distance/Time)=(200/112.4)=1.78 meters per second

From the speeds for each we can conclude that;

Emily's speed(1.78 m/s)>Robert's speed(1.66 m/s)>Deborah's speed(1.23 m/s)

Emily's speed is the greatest, therefor she is the fastest at a speed of 1.78 m/s

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Answer:

g=56

Step-by-step explanation:

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For example,

if the sides in triangle 1 were a and b, and triangle 2 had side lengths c and d, c and a had the same ratios, and b and d had the same ratios

and triangle 1 was similar to triangle 2, the ratio between the sides of the triangles would be

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What that means is that in this situation, 8/5=g/35.

8/5=g/35

Cross multiply.

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3 years ago
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Answer:

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Step-by-step

i simplified it if thats what it meant

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3 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
AURORKA [14]

Answer:

(−0.103371 ; 0.063371) ;

No ;

( -0.0463642, 0.0063642)

Step-by-step explanation:

Shift 1:

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Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm

Shift 2:

Sample size, n2 = 25

Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17

Mean difference ; μ1 - μ2

Zcritical at 95% confidence interval = 1.96

Using the relation :

(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)

(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)

Lower boundary :

-0.02 - 0.0833710 = −0.103371

Upper boundary :

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B.)

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C.)

For sample size :

n1 = 300 ; n2 = 250

(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)

Lower boundary :

-0.02 - 0.0263642 = −0.0463642

Upper boundary :

-0.02 + 0.0263642 = 0.0063642

( -0.0463642, 0.0063642)

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3 years ago
Find the slope of the line that contains <br>(0,4). <br>(5,0)​
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Answer:   -4/5

Step-by-step explanation:

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