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Gemiola [76]
3 years ago
11

There is a language with 12 distinct letters. How many words that are less than four letters long can possibly be formed? (Assum

e any combination of letters is valid and letters can be repeated). Can you help me out with this one?
Mathematics
1 answer:
allochka39001 [22]3 years ago
8 0

Answer:

1884

Step-by-step explanation:

1)If you hear the condition "less than four letters" it means that each word can consist of 3,2 or 1 letter. Firstly, consider the easiest situation with the word from one letter. There are 12 letters, so there are 12 words from one letter.

Then the words from two letters. The first letter of such a word can be chosen in 12 means(because 12 letters are available), then the second letter can be chosen in 12 means too. 12*12=144 words with 2 letters. (Multiplying, not adding, because each two words form one combination).

Then for the words from three letters, use the same rule, 12 means for the first letter, 12 means for the second letter, 12 means for the third letter. 12*12*12=1728 words.

Having particular words from 1,2,3 letters add them to get total quantity of words: 12+144+1728=1884words,that is the answer.

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The table displays the number of students in each grade at Richmond High School who will or will not be attending the amusement
Pani-rosa [81]

Answer:

P( eleventh\: \: |\: \: FT)=  0.2453 \\\\P( eleventh\: \: |\: \: FT)=  24.53\% \\\\

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

P(eleventh\:  and \: FT) = \frac{13}{92}  \\\\P(eleventh \:  and \: FT) = 0.1413

Where P(FT) is the probability of students who will be going to field trip

P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\

So the required probability is

P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)=  0.2453 \\\\P( eleventh\: \: |\: \: FT)=  24.53\% \\\\

6 0
3 years ago
6y+2+9x how many terms are there in the algebraic expression
TiliK225 [7]

Answer: 3

Step-by-step explanation:

6y (1)

2 (2)

9x (3)

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3 years ago
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Step-by-step explanation:

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Answer:

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5 0
3 years ago
Convert to a fraction: 150%
BARSIC [14]
So,  all percents can be expressed as *percent*/100
So for this,  it would be 150/100
Then we want to simplify it down and all that jazz.  Find the biggest number that BOTH the numerator AND denominator can be divided by.
In this case,  50.
150/50=3
100/50=2
So now you have 3/2
You might also want a mixed number,  or, a whole number with the leftover fraction after it.
In this case,  see how many times can 2 go into 3 FULLY.
The answer would be 1.  1 is our WHOLE NUMBER.
Then take whatever is left over from 3 and that is our numerator.  Do this,  since 2 can go into 3 ONE time FULLY,  I can say 3-(2*1) is our remainder.
That gives you one as the numerator.  2 is still the denominator.
So a mixed number of 3/2 is 1 1/2
So here is 150% as a fraction:  150/100,  3/2 or 1 1/2.
I hope I helped!!! -Kibeye/Ethan
6 0
4 years ago
Read 2 more answers
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