B is 34 mm from the center of circle O, which has radius 16 mm. BP and BR are tangent segments. AC is tangent to O at point Q. F
ind the perimeter of ABC?
1 answer:
Answer:
56.72mm
Step-by-step explanation:
BQ = 34 - 16 = 18mm
Using similar triangle,
AQ = QC =(16*18)/34 = 8.47mm
AC = 2*8.47 = 16.94 mm
Since
BC = AB = sqrt( AQ² + BQ²)
BC = AB = sqrt( 8.47² + 18²)
BC = AB = 19.89mm
Perimeter of triangle ABC = AB + BC + AC
P = 19.89 + 19.89 + 16.94
Perimeter = 56.72mm
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