Answer:There are 72 heads (chicken and rabbit) and 200 legs. How many chickens and rabbits are present totally?
Step-by-step explanation
There are 72 heads (chicken and rabbit) and 200 legs. How many chickens and rabbits are present totally?
Legs of a chicken = 2
Legs of a rabbit = 4
Total heads = 72
Total legs= 200
Let's assume that each of them has minimum 2 legs.
So 72*2 = 144 legs
Remaining legs: 200-144= 56
These remaining legs belong to rabbit because rabbit has 4 legs each.
2*Rabbits= 56
Rabbits= 56/2 = 28
Out of 72, 28 are rabbits. So there are 72-28= 44 chicken.
Answer:
The number of cases in the year 2010 is 266.
Step-by-step explanation:
An exponential function is one that the independent variable x appears in the exponent and has a constant a as its base. Its expression is:
f(x)=aˣ
being a positive real, a> 0, and different from 1, a ≠ 1.
In this case:

where t is the number of years since 1960 and e is an irrational number of which it is not possible to know its exact value because it has infinite decimal places. The first figures are 2,7182818284590452353602874713527 and is often called the Euler's number. e is the base of natural logarithms.
In this case, you want to know the number of cases r (t) in 2010. So, to know t you must know how many years have passed since 1960. For that, you can simply do the following subtraction: 2010-1960 and you get as a result : 50.
Replacing in the exponential expression r (t):

Solving:
r(t)=265.79 ≅ 266
<u><em>The number of cases in the year 2010 is 266.</em></u>
Answer:
the answer would be 2 * 2 * y √2 * 5* 7 * y
Step-by-step explanation:
Answer:
64.5
Step-by-step explanation:
64.5