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Julli [10]
3 years ago
13

Katie cut out a rectangular piece of wrapping paper that was 2 times as long and 3 times as wide as the box that she was wrappin

g. The box was 5inches long and 4 inches wide. What is the perimeter of the wrapping paper that katie cut?
Mathematics
2 answers:
Dmitry [639]3 years ago
8 0
2×5=10
3×4=12
10+10+12+12=44 inches
you add 10 and 12 twice because you have to account for the top and bottom of the piece of wrapping paper as well as the left and right sides of it
Lisa [10]3 years ago
8 0
Answer: the perimeter of the wrapping paper Katie cut was 44in².

explanation: if the box's length is 5in., that means you to multiply by 2 because she cut it 2x as much as the length as the box, if the box's width was 4in., then you have to multiply by 3 since she cut it 3x as much of the width as the box itself.

Now, you have to add both products to get your perimeter:

equation: (5×2) + (4×3) = 44
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7y^2+15x-22. Y=4. ×=5
Nutka1998 [239]

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3 0
3 years ago
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artcher [175]

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7 0
3 years ago
IF A= -35 , B = 10 , C= -5 verify that:-<br>a x (b+c) = a x b + a x c<br><br>Plz tell​
Luda [366]

Answer:

see below

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6 0
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