C. is the answer.
The modulus or absolute value function of a real number x is the non-negative value of x without regard to its sign.
The only correct option is C. because 15 is indeed greater than 12.
Options A., B., D. and E. are wrong.
Answer:
The square root of 162 in its simplest form means to get the number 162 inside the radical √ as low as possible.
Here is how to do that! First we write the square root of 162 like this:
√162
The largest perfect square of the factors of 162 is 81. We can therefore convert √162 like this:
√81 × 2
Next, we separate the numbers inside the √ as such:
√81 × √2
√81 is a perfect square that equals 9. We can therefore put 9 outside the radical and get the final answer to square root of 162 in simplest radical form as follows:
9√2
Step-by-step explanation:
Simplify both sides if needed. The left-hand side needs simplification.
4(x - 6)
-2x + 6
4x - 24
-2x + 6
All is left to do is add and subtract to get the x variable all alone.
4x - 24
-2x + 6
6x - 24
6 <-- Add 2x to both sides
6x
30 <-- Add 24 to both sides
x
5 <-- Divide both sides by 6
In order to be in the solution set, x has to be less than or equal to 5.
In interval notation: [5, -∞)
Ans
Step-by-step explanation:
Answer:
we conclude that:
Step-by-step explanation:
Given
f(x) = x+9
g(x) = x² + 7x – 14
To determine
g(f(-5)) = ?
First, we need to find f(-5)
f(x) = x+9
substitute x = -5
f(-5) = (-5)+9
f(-5) = -5+9
f(-5) = 4
so
g(f(-5)) = g(4)
Now, we need to find g(4)
g(x) = x² + 7x – 14
substitute x = 4
g(4) = (4)² + 7(4) - 14
g(4) = 16 + 28 - 14
g(4) = 30
i.e.
g(f(-5)) = g(4) = 30
Therefore, we conclude that:
