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alexira [117]
2 years ago
10

Five hundred randomly selected working adults living in Calgary, Canada were asked how long, in minutes, their typical daily com

mute was (Calgary Herald Traffic Study, Ipsos, September 17, 2005). The resulting sample mean and standard deviation of commute time were 28.5 minutes and 24.2 minutes, respectively. Construct and interpret a 90% confidence interval for the mean commute time of working adult Calgary residents.
Mathematics
1 answer:
Anarel [89]2 years ago
5 0

Answer:

90% confidence interval for the mean commute time of working adult Calgary residents is between a lower limit of 26.72 minutes and an upper limit of 30.28 minutes.

Step-by-step explanation:

Confidence Interval = Mean + or - Error margin (E)

mean = 28.5 minutes

sd = 24.2 minutes

n = 500

degree of freedom = n - 1 = 500 - 1 = 499

confidence level = 90%

t-value corresponding to 499 degrees of freedom and 90% confidence level = 1.64801

E = t × sd/√n = 1.64801 × 24.2/√500 = 1.78

Lower limit = mean - E = 28.5 - 1.78 = 26.72 minutes

Upper limit = mean + E = 28.5 + 1.78 = 30.28 minutes

90% confidence interval is between 26.72 and 30.28 minutes.

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Mr. Ortiz has 3/4 pound of oatmeal.
ki77a [65]

Answer:

\frac{1}{4}\ pound

Step-by-step explanation:

We\ are\ given:\\Amount\ of\ oatmeal\ Mr.Ortiz\ has=\frac{3}{4}\ pounds \\Amount\ of\ Oatmeal\ he\ uses\ to\ bake\ muffins=\frac{2}{3}\ of\ the\ amount\ he\ had\\Now,\\Lets\ first\ find\ the\ amount\ of\ oatmeal\ he\ used=\frac{3}{4}*\frac{2}{3}=\frac{1}{2}\ pounds\\Hence,\\The\ amount\ of\ oatmeal\ remains=Total\ amount\ of\ oatmeal-Amount\\ he\ used\ to\ make\ muffins\\Hence,\\The\ amount\ of\ oatmeal\ left\ with\ Mr.\ Ortiz=\frac{3}{4} - \frac{1}{2} =\frac{1}{4}\ pound

5 0
3 years ago
I need help with this question! will give thanks :)))
topjm [15]

Answer:

2\sqrt{13}

Step-by-step explanation:

Use the distance formula and plug in the values

d=(3−(−3))2+(2−6)2√  

d=(6)2+(−4)2√

d=36+16√

d=\sqrt{52}

d= 2\sqrt{13}

6 0
2 years ago
Cylinders A and B are similar. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.
MrRa [10]

The question is incomplete. The complete question is :

Cylinders A and B are similar. The length of the cylinder A is 4 mm and the length of cylinder B is 6 mm. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

Answer:

67.5 mm^3

Step-by-step explanation:

Given that :

Cylinder A and cylinder B are similar.

Let volume of cylinder A = 20 mm^3

We know the volume of a cylinder is given by V = $\pi r^2 h$

where, r is the radius of the cylinder

            h is the height of the cylinder

We have to find the scale factor.

The length scale factor is = $\frac{6}{4}$

                                          $=\frac{3}{2}$

Area scale factor $=\left(\frac{3}{2}\right)^2$

                           $=\frac{9}{4}$

∴ Volume scale factor $=\left(\frac{3}{2}\right)^3$

                                     $=\frac{27}{8}$

Therefore, the volume of cylinder B is $=20 \times \frac{27}{8}$

                                                               = 67.5 mm^3

5 0
3 years ago
Whats the answer to this problem????<br><br><br>the product of 6 and a number p is 24
Ad libitum [116K]
Well the P should probably be 4
7 0
2 years ago
SOLVE 3/4 +(1/3/1/6) -(1/2)
jarptica [38.1K]

Answer:9/4

Step-by-step explanation:

3/4 + (1/3/1/6) - (1/2)

3/4 + (1/3 ➗ 1/6) - 1/2

3/4 + (1/3 x 6/1) - 1/2

3/4 + ((1x6)/(3x1)) - 1/2

3/4 + (6/3) - 1/2

3/4 + 2 - 1/2

(3+8-2)/4

9/4

8 0
3 years ago
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