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2 years ago

Will mark Brainliest please answer

Mathematics

1 answer:

zheka24 [161]2 years ago

4 0

Answer:

A. (-1,-2)

Step-by-step explanation:

hope this helps :) and can i ask is that a leg next to the screen?

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Sweaters are $3 for $50. Leslie and her mother spent $100 on sweaters. How many did they buy

inn [45]

Answer:

Step-by-step explanation:

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2 years ago

320 students are going on a field trip 60 per bus how many buses should be ordered

EastWind [94]

Answer:

Step-by-step explanation:

320:60 you have to find the multiples I am not going to give you the full answer that is cheating

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2 years ago

1) (-16, 19), (17, 20)<br> find the slope

Reptile [31]

Answer:

you have to do rise over run... y2-y1/ x2-x1.

1/33

Step-by-step explanation:

I don't know if i'm correct but thats what I got. Due to 20 minus 19 is 1. and 17 minus -16 equals 33.

4 0

2 years ago

2[3(4^2 +1)] - 2^3.

Sav [38]

Answer:

Step-by-step explanation:

Do parentheses first, exponents inside them first. 4^2 = 16, + 1 is 17, then multiply by the 3 outside to get 51, then multiply by the 2 outside that to get 102, - 2^3 which is -8 = 94

7 0

3 years ago

Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec

expeople1 [14]

Answer:

$cot x = \frac{cos x}{sin x}$

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

$cos x cot x + sin x$

We know from math properties that the definition for cot is $cot x = \frac{cos x}{sin x}$

If we use this definition we got:

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

Now we can use the following identity:

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

4 0

3 years ago