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strojnjashka [21]

3 years ago

13

Robinson Manufacturing found the following information in its accounting records: $ 519 comma 800 of direct materials used, $

226 comma 700 of direct labor, and $ 775 comma 800 of manufacturing overhead. The Work in Process Inventory account had a beginning balance of $ 72 comma 400 and an ending balance of $ 87 comma 600. Compute the company's Cost of Goods Manufactured.

1 answer:

Damm [24]3 years ago

5 0

Answer:

Cost of good manufactured= $1507100

Explanation:

To calculate the cost of manufactured goods we need to use the following formula:

Cost of good manufactured= Beginning work in progress+ direct materials of the period + direct labor + manufactured overhead - ending work in progress

Beginning work in progress= 72400

Direct materials = beginning inventory + purchase - ending inventory= 519800

Direct labor= 226700

Manufactured overhead= 775800

Ending work in progress= 87600

Cost of good manufactured= 72400 + 519800 + 226700 + 775800 - 87600= $1507100

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After graduating from dental school two years ago, Dr. Lauren Farish purchased the dental practice of a long-time dentist who wa

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Answer:

Total cost formula= 3,510 + 4.911*x

x= Number of instruments

Explanation:

<u>To calculate the variable and fixed costs, we will use the high-low method:</u>

Variable cost per unit= (Highest activity cost - Lowest activity cost)/ (Highest activity units - Lowest activity units)

Variable cost per unit= (10,012 - 6,574) / (1,324 - 624)

Variable cost per unit= $4.911

Fixed costs= Highest activity cost - (Variable cost per unit * HAU)

Fixed costs= 10,012 - (4.911*1,324)

Fixed costs= $3,510

Fixed costs= LAC - (Variable cost per unit* LAU)

Fixed costs= 6,574 - (4.911*624)

Fixed costs= $3,510

Total cost formula= 3,510 + 4.911*x

x= Number of instruments

For 1,192 instruments:

Total cos= 3,510 + 4.911*1,192

Total cost= $9,363.9

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2 years ago

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3 years ago

Which of the following is a potential advantage to working in a commercial fitness facility?A. Can work from homeB. In-house emp

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Answer: Option B

Explanation: In simple words, commercial fitness facility refers to the gymnasiums an other such facility centers where individuals can go and work out for a better health and fitness. In house training refers to the knowledge that an employee gains while working for an organisation.

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3 years ago

Assume that there are 5 different issues of sports illustrated, 6 different issues of newsweek, and 3 different issues of time,

Genrish500 [490]

Answer:

a. P(1 Sports illustrated and 3 Newsweek) = $\frac{100}{1001}$

b. P(at least 2 Newsweek) = $\frac{595}{1001}$

We follow these steps to arrive at the answer:

The total number of magazines is $5+6+3 =14$

Of these we need to choose 4 books randomly. Since order doesn’t matter here, we use combinations.

There are $_{14}C_{4}$ ways to choose 4 books.

$_{14}C_{4}=\frac{14!}{10!4!} = 1001 ways$

1. 1. We need to choose 1 Sports illustrated and 3 newsweeks.

We can choose 1 Sports illustrated from 5 in $_{5}C_{1}$ ways.

$_{5}C_{1}=\frac{5!}{4!1!} = 5 ways$

We can choose 3 issues of Newsweek in $_{6}C_{3}$ ways.

$_{6}C_{3}=\frac{6!}{3!3!} = 20 ways$

So,

$P(1 Sports Illustrated and 3 Newsweek) = \frac{_{6}C_{3} * _{5}C_{1}}{_{14}C_{4}}$

$P(1 Sports Illustrated and 3 Newsweek) = \frac{20 * 5}{1001}$

$P(1 Sports Illustrated and 3 Newsweek) = \frac{100}{1001}$

2.<u> P(at least 2 Newsweek)</u>

Here we divide the number of books into two categories. One is the Newsweek Magazines (6), the other group consists of all other books (8).

$P(at least 2 Newsweek) = 1 - [P(no Newsweek) + P(one newsweek)]$

Now, if we have to find P(no newsweek), we first need to find the number of ways we can select 4 books from the group that does NOT contain Newsweek magazines.

We can calculate that by:

${ _{8}C_{4} = \frac{8!}{4!4!} = 70 ways$

So,

$P(no newsweek) = \frac{70}{1001}$

We can compute P(1 Newsweek) as follows:

We can choose 1 Newsweek in $_{6}C_{1} =\frac{6!}{5!1!} = 6 ways$

We can choose 3 other books in $_{8}C_{3} =\frac{8!}{5!3!} = 56 ways So, P(at least 1 Newsweek) = [tex]\frac{6*56}{1001} or \frac{336}{1001}$

Since

$P(at least 2 Newsweek) = 1 - [P(no Newsweek) + P(one newsweek)]$ ,

$P(at least 2 Newsweek) = 1 - [\frac{70}{1001} + \frac{336}{1001}]$

$P(at least 2 Newsweek) = 1 - [\frac{406}{1001}]$

$P(at least 2 Newsweek) = \frac{595}{1001}$

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3 years ago