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Nutka1998 [239]
3 years ago
14

Is 4x-3=19 true,false,or open

Mathematics
2 answers:
jasenka [17]3 years ago
4 0

Answer:

True

Step-by-step explanation:

With questions like these, you can put any number in the option to make it correct. HOWEVER, in this question, the only correct answer would be 5.5.

igomit [66]3 years ago
3 0

Answer:

True

Step-by-step explanation:

4x-3=19

4x = 19 + 3

4x = 22

x = 22/4

x = 11/2

x = 5 1/2

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The revenue, in dollars, of a company that makes toy cars can be modeled by the polynomial 3x2 + 4x – 60. The cost, in dollars,
Tems11 [23]

For this case we have the following quadratic functions:

Revenue: 3x ^ 2 + 4x - 60

Cost: 3x ^ 2 - x + 200

Then, we observe that the profit is given by the following mathematical relationship:

Profit = Revenue - Cost

Substituting values we have:

Profit = (3x ^ 2 + 4x - 60) - (3x ^ 2 - x + 200)

Making the corresponding calculations we have:

Profit = x ^ 2 (3-3) + x (4 + 1) + (-60-200)\\Profit = 5x - 260

Answer:

An expression that represents the profit is:

Profit = 5x - 260

4 0
3 years ago
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galben [10]

Answer:

Y= 3

Step-by-step explanation:

When the line hits - 1

The y axis shows that its 3

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3 years ago
Kelso is in charge of a bake sale. On each table, t, there will be a platter of 24 cookies and 2 bowls of brownies with b browni
Phantasy [73]
24*7 = 168
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336 Total sweets

8 0
3 years ago
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RUDIKE [14]

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Step-by-step explanation:

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3 years ago
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Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
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