Answer:
<h2>Step-by-step explanation:
Given,
There are 8 seats in a row.
There are 8 seats in a row.4 seats are occupied.
Available seats = 8 - 4 = 4 seats
Fraction of seats available:
Reduce the fraction with GCF 4
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Math problem time lol
2 answers:
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8. 1/2
(0.2 is half)
(0.2 is half)
Answer:
The second bus catch the first bus after 8 hours
Step-by-step explanation:
Given as :
The speed of first bus = 40 mph
The first bus start at = T hour
The speed of second bus = 50 mph
The second bus followed first bus after 2 hour = ( T - 2 ) hour
Since distance cover by both buses are same = D
So , Distance = Speed × Time
Or, For First bus , D = 40 mph × T
For second bus , D = 50 mph × ( T - 2 )
I.e 40 × T = 50 × T - 100
or, 100 = 50 × T - 40 × T
Or, 100 = 10 × T
∴ T = = 10 h
Now since The second bus followed first bus after (T - 2 ) hour = 10 - 2 = 8 h
Hence The second bus catch the first bus after 8 hours Answer