Assuming that this company sells all that it produces, the profit function would be given by P(x) = -0.5(x - 100)² + 5,000 - 50x - 100.
<h3>What is profit?</h3>
In Economics, profit can be defined as a measure of the amount of money (revenue) that is generated when the selling price is deducted from the cost price of a good or service, which is usually provided by producers.
This ultimately implies that, all producers generally work to maximize their profits and make them as large as possible, in order to enable them break even and successful.
Mathematically, the profit function P(x) of a business firm simply refers to the revenue function R(x) minus the cost function C(x):
P(x) = R(x) - C(x)
Where:
- R(x) represents how much it takes in.
- C(x) represents how much it spends.
Substituting the given parameters into the formula, we have;
P(x) = -0.5(x - 100)² + 5,000 - (50x + 100)
P(x) = -0.5(x - 100)² + 5,000 - 50x - 100
Read more on maximized profit here: brainly.com/question/13800671
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Bridge communication is the best solution to continue two different building for the same company.
<u>Explanation:</u>
Bridge communication to be placed in both building.master device should be placed in one building where should be connected to a high-end server and the slave device should be placed in another device.
Both the master device and salve should have a subsequent TCPIP address. For example, if the master TCPIP address is 192.168.1.51 and the salve Tcpip address should be 192.168.1.52.
Very easy configure and communication is established. Both devices should be connected with nonstop current interruption. Once communication established speed depends on device capacity.
Answer:
dominance
Explanation:
i just took it and got it right
Answer:
PROGRAM QuadraticEquation
Solver
IMPLICIT NONE
REAL :: a, b, c
;
REA :: d
;
REAL :: root1, root2
;
//read in the coefficients a, b and c
READ(*,*) a, b, c
WRITE(*,*) 'a = ', a
WRITE(*,*) 'b = ', b
WRITE(*,*) 'c = ', c
WRITE(*,*)
// computing the square root of discriminant d
d = b*b - 4.0*a*c
IF (d >= 0.0) THEN //checking if it is solvable?
d = SQRT(d)
root1 = (-b + d)/(2.0*a) // first root
root2 = (-b - d)/(2.0*a) // second root
WRITE(*,*) 'Roots are ', root1, ' and ', root2
ELSE //complex roots
WRITE(*,*) 'There is no real roots!'
WRITE(*,*) 'Discriminant = ', d
END IF
END PROGRAM QuadraticEquationSolver
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