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viktelen [127]
3 years ago
6

Mike needs to write the primary objectives of a project in a project plan. In which section should he write them?

Computers and Technology
1 answer:
Advocard [28]3 years ago
7 0

Mike needs to write the primary objectives of a project in a project plan. He should write this under the SCOPE section of the project plan.

Explanation:

  • Project scope is the part of project planning that involves determining and documenting a list of specific project goals, deliverables, features, functions, tasks, deadlines, and ultimately costs.
  • It is what needs to be achieved and the work that must be done to deliver a project.
  • The Scope of Work (SOW) is the area in an agreement where the work to be performed is described.
  • The SOW should contain any milestones, reports, deliverables, and end products that are expected to be provided by the performing party. The SOW should also contain a time line for all deliverables.
  • The scope is simply all the work that needs to be done in order to achieve a projects objectives.
  • A project scope, or project scope statement, is a tool used to describe the major deliverables of a project including the key milestones, high level requirements, assumptions, and constraints.

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simplify the expression below and state the value of m for which the simplified expression is not defined 2m² + m - 15/ m² - 9​
motikmotik

Answer:

  • The simplified expression is: \frac{2m-5}{m-3}
  • The simplified expression is undefined for m=3

Explanation:

The given expression is:

\frac{2m^2+m-15}{m^2-9}

The numerator can be siplified by using factorization and denominator will be simplified using the formula

a^2-b^2 = (a+b)(a-b)

So,

= \frac{2m^2+6m-5m-15}{(m)^2-(3)^2}\\=\frac{2m(m+3)-5(m+3)}{(m-3)(m+3)}\\=\frac{(2m-5)(m+3)}{(m-3)(m+3)}\\=\frac{2m-5}{m-3}

A fraction is undefined when the denominator is zero. In order to find the value of m on which the simplified fraction will be undefined we will put denominator equal to zero.

So,

m-3 = 0 => m = 3

Hence,

  • The simplified expression is: \frac{2m-5}{m-3}
  • The simplified expression is undefined for m=3
7 0
2 years ago
What is the difference between a rendering engine and a browser engine?
Vlada [557]

Answer:

D) A rendering engine displays content on the screen and a browser engine coordinates user interface interactions.

Explanation:

The rendering engine will deal with all the HTML code and will generate an output based on its own rules for interpreting the code.  That's why different rendering engines will have different renditions of the same given HTML code. You can notice that in the acceptance of HTML5 and CSS3 tags, which are not universal yet.

The browser engine will deal with the user interface and all other features that make a browser a browser, relying on the rendering engine for the display.

That duality allows different browsers to use the same rendering engine, thus have similar outputs.

7 0
2 years ago
Read 2 more answers
Write a program that asks the user to enter a number of seconds. There are 60 seconds in a minute. If the number of seconds ente
frez [133]

Answer:

// here is code in c.

#include <stdio.h>

// main function

int main()

{

// variable to store seconds

long long int second;

printf("enter seconds:");

// read the seconds

scanf("%lld",&second);

// if seconds is in between 60 and 3600

if(second>=60&& second<3600)

{

// find the minutes

int min=second/60;

printf("there are %d minutes in %lld seconds.",min,second);

}

// if seconds is in between 3600 and 86400

else if(second>=3600&&second<86400)

{

// find the hours

int hours=second/3600;

printf("there are %d minutes in %lld seconds.",hours,second);

}

// if seconds is greater than 86400

else if(second>86400)

{

// find the days

int days=second/86400;

printf("there are %d minutes in %lld seconds.",days,second);

}

return 0;

}

Explanation:

Read the seconds from user.If the seconds is in between 60 and 3600 then find the minutes by dividing seconds with 60 and print it.If seconds if in between 3600 and 86400 then find the hours by dividing second with 3600 and print it. If the seconds is greater than 86400 then find the days by dividing it with 86400 and print it.

Output:

enter seconds:89

there are 1 minutes in 89 seconds.

enter seconds:890000

there are 10 days in 890000 seconds.

8 0
2 years ago
Give a pseudo-code description of the O(n)-time algorithm for computing the power function p(x,n).Also draw the trace of computi
laila [671]

Answer:

p(x,n)

1. if(n==0)    [if power is 0]

2.    then result =1.

3.else

4. {    result=1.

5.      for i=1 to n.

6.          {  result = result * x. }  [each time we multiply x once]

7.       return result.

8.  }

Let's count p(3,3)

3\neq0, so come to else part.

i=1: result = result *3 = 3

i=2: result = result *3 = 9

i=2: result = result *3 = 27

Explanation:

here the for loop at step 4 takes O(n) time and other steps take constant time. So overall time complexity = O(n)

6 0
3 years ago
The BIOS feature that enables a hard drive to read or write several sectors at a time is called what?
lukranit [14]

The BIOS feature that enables a hard drive to read or write several sectors at a time is called IDE block mode

Explanation:

IDE block mode setting speeds up IDE drivers when enabled by allowing multiple sectors to read or write operations. This BIOS feature rushes up hard disk drive passage by transferring many divisions of data per interrupt rather than using the normal single-sector transfer mode.

This mode of transfer is known as block transfers. When block transfers are enabled, depends on the IDE controller, nearly 64 KB of data can be transferred per interrupt.

4 0
3 years ago
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