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goblinko [34]
3 years ago
15

Software obtained illegally is called open-source software. true / false

Computers and Technology
1 answer:
Oxana [17]3 years ago
3 0
False, software obtained illegally is called Pirated Software.
<span>Open source software is software developed by and for the user community, ie. Linux based software is Open Source.</span>
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This graph shows a relationship between the height of a giraffe and its weight which term describe the dashed line through the g
Nadusha1986 [10]

Answer: The Answer is C

Explanation: This is because It is mainly controlled by genetics and we can not manipulate genetics.

4 0
3 years ago
Read 2 more answers
Code a complete Java program to load and process a 1-dimensional array.
zepelin [54]

Answer:

Here you go.Consider giving brainliest if it helped.

Explanation:

import java.io.*;//include this header for the file operation

import java.util.*;//to perform java utilities

import javax.swing.JOptionPane;//needed fro dialog box

class Driver{

  public static void main(String args[]){

      int wages[]=new int[15];//array to hold the wages

      int index=0;

      try{

          //use try catch for the file operation

          File file=new File("wages.txt");

          Scanner sc=new Scanner(file);//pass the file object to the scanner to ready values

          while(sc.hasNext()){

              String data=sc.nextLine();//reads a wage as a string

              String w=data.substring(1);//remove the dollar from the string data

              wages[index++]=Integer.parseInt(w);//convert the wage to int and store it in the array

          }

          sc.close();//close the scanner

      }catch(FileNotFoundException e){

          System.out.println("Error Occurrred While Reading File");

      }

     

      //sort the array using in built sort function

      Arrays.sort(wages);

      //print the wages

      System.out.println("Wages of 15 person in ascending order:");

      for(int i=0;i<wages.length;i++){

          System.out.print("$"+wages[i]+" ");

      }

      //call the increases wages method

      wages=increaseWages(wages);//this method return the updated wages array

     

  }

 

  //since we can call only static methods from main hence increaseWages is also static

  public static int[] increaseWages(int wages[]){

      //increase the wages

      for(int i=0;i<wages.length;i++){

          wages[i]+=500;

      }

     

      //print the new wages

      int sum=0;

      System.out.println("\n\nNew wages of 15 person in ascending order:");

      for(int i=0;i<wages.length;i++){

          sum+=wages[i];//sums up the new wages

          System.out.print("$"+wages[i]+" ");

      }

     

      //display the summation of the new wages in a dialog box

      JOptionPane.showMessageDialog(null,"Total of new wages: "+sum);

      return wages;

  }

}

6 0
3 years ago
What two devices are often connected into one device in a small network to connect the home network to the internet and to share
bagirrra123 [75]
The two devices are modem and router! 
3 0
3 years ago
How does Accenture view automation?
tia_tia [17]

Answer:

The description of the given question is summarized below.

Explanation:

  • These organizations retrained, retooled, and empowered our employees amongst all organization's internal management operating areas throughout order to create an increased automation attitude.
  • Accenture's Innovative Software department was indeed adopting a concept called Human Plus technology, which includes this type of training.
5 0
2 years ago
Write an if-else statement to describe an integer. Print "Positive even number" if isEven and is Positive are both true. Print "
Nina [5.8K]

Answer:

C code explained below

Explanation:

#include <stdio.h>

#include <stdbool.h>

int main(void) {

int userNum;

bool isPositive;

bool isEven;

scanf("%d", &userNum);

isPositive = (userNum > 0);

isEven = ((userNum % 2) == 0);

if(isPositive && isEven){

  printf("Positive even number");

}

else if(isPositive && !isEven){

  printf("Positive number");

}

else{

  printf("Not a positive number");

}

printf("\n");

return 0;

}

6 0
3 years ago
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