Answer:

Step-by-step explanation:
We have the following solution:

We want to find the value of x that satisfies the following condition:
y(3) = 3.
This means that when x = 3, y = 3. So







Answer:
<u>1. Mean = 342.7 (Rounding to the nearest tenth)</u>
<u>2. Median = 167.5 </u>
<u>3. Mode = There isn't a mode for this set of numbers because there isn't a data value that occur more than once. </u>
Step-by-step explanation:
Given this set of numbers: 107, 600, 115, 220, 104, 910, find out these measures of central tendency:
1. Mean = 107 + 600 + 115 + 220 + 104 + 910/6 = <u>342.7</u> (Rounding to the nearest tenth)
2. Median. In this case, we calculate it as the average between the third and the fourth element, this way:
115 + 220 =335
335/2 = <u>167.5 </u>
3. Mode = <u>There isn't a mode for this set of numbers because there isn't a data value that occur more than once. All the data values occur only once.</u>
Answer:
The determinant is 15.
Step-by-step explanation:
You need to calculate the determinant of the given matrix.
1. Subtract column 3 multiplied by 3 from column 1 (C1=C1−(3)C3):
![\left[\begin{array}{ccc}-25&-23&9\\0&3&1\\-5&5&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%26-23%269%5C%5C0%263%261%5C%5C-5%265%263%5Cend%7Barray%7D%5Cright%5D)
2. Subtract column 3 multiplied by 3 from column 2 (C2=C2−(3)C3):
![\left[\begin{array}{ccc}-25&-23&9\\0&0&1\\-5&-4&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%26-23%269%5C%5C0%260%261%5C%5C-5%26-4%263%5Cend%7Barray%7D%5Cright%5D)
3. Expand along the row 2: (See attached picture).
We get that the answer is 15. The determinant is 15.
Answer:
180
Step-by-step explanation:
So, lets go over what we know:
5% of x = 9
Thinking of this in decimal form, this is:
0.05 * x = 9, or 0.05x = 9
To find the answer, we must multiply both sides to get 1x.
Since 0.05 is 1/20 of 1, we must multiply both sides by 20:
0.05x * 20 = 0 * 20:
1x = 180
So the answer is 180!
Hope this helps!
<u>Answer:</u>
0 ≤ x ≤ π
<u>Step-by-step explanation:</u>
In order to define the inverse cosine functions, the domains of the cosine functions are restricted.
One major condition to define an inverse of a function is that the original function must be one‐to‐one which means that one value from the domain should correspond to only one value in the range.
So we have a restriction that is placed on the values of the domain of the cosine function which is the following:
0 ≤ x ≤ π