On hypotenuse of the triangle .
Right bisectors of the sides of a right triangle triangle meet hypotenuse.
Answer: THE ANSER IS A. No, the domain value 5 corresponds to two range values, -8 and 5.
Find the domain and range.
Domain:
{
6
, 5 ,
1
}
Range:
{
−
7
, −
8 ,
4 ,
5
}
Step-by-step explanation: IT'S NOT C OR D
Determine if the relation is a function.
The relation is not a function.
we have M is durectly porpotional to r^2
so M=(k)r^2
and when r=2, m=14
so 14=(k)(2)^2
k=14/4 =7/2
so when r=12
m= (7/2)(12)^2 =(7/2)(144) = 504
it's a right angled triangle so we will use hypotenuse formula to get the value of x
hypotenuse formula = a² + b² = c²
a = side of the triangle
b = base of traingle
c = hypotenuse ( can be written as h too)
and the formula can also be written as.
c² = a² + b²
<em><u>therefore</u></em><em><u>,</u></em><em><u> </u></em><em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u>1</u></em>
<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care!</u></em>
Hello,
x²+2*3x+3²+7-9=0
==>(x+3)²-2=0
==>(x+3-√2)(x+3+√2)=0
==> x=-3+√2 or x=-3-√2