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natka813 [3]
4 years ago
7

How to factor 5x^2 +4x -1

Mathematics
1 answer:
Kazeer [188]4 years ago
4 0
5x^2+4x-1\\\\Method\ 1:\\\\5x^2+4x-1=5x^2+5x-x-1=5x(x+1)-1(x+1)\\=(x+1)(5x-1)\\\\5x^2+4x-1=(x+1)(5x-1)\\\\Method\ 2:\\\\5x^2+4x-1\\a=5;\ b=4;\ c=-1\\\\\Delta=b^2-4ac\\\\\Delta=4^2-4\cdot5\cdot(-1)=16+20=36 \ \textgreater \  0\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{36}=6\\\\x_1=\dfrac{-4-6}{2\cdot5}=\dfrac{-10}{10}=-1\\\\x_2=\dfrac{-4+6}{2\cdot5}=\dfrac{2}{10}=0.2\\\\5x^2+4x-1=5(x-0.2)(x+1)=(5x-1)(x+1)
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The point (-3,-1) lies in the quadrant: A.​
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Answer:

\displaystyle QUADRANT\:III

Step-by-step explanation:

\displaystyle [POSITIVE, NEGATIVE] → QUADRANT\:IIII \\ [NEGATIVE, NEGATIVE] → QUADRANT\:III \\ [NEGATIVE, POSITIVE] → QUADRANT\:II \\ [POSITIVE, POSITIVE] → QUADRANT\:I

I am joyous to assist you at any time.

3 0
3 years ago
The height of a box that joan is shipping is 3 inches less than the width of the box. the length is 2 inches more than twice the
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We first recall the formula for the volume of a rectangular box:
V=l*w*h where l is its length, w is the width, and h is the height.

According to the problem, the height is 3 inches less than the width therefore we can replace h with the term w-3. Additionally, the length of the box is 2 inches more than twice the width therefore the length can also be replaced with 2w+2.

We can notice that the equation will just have one unknown variable because we already know the volume of the box. We can then solve for this variable (w):

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7 0
4 years ago
ALICE
Mice21 [21]

Answer:

A

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The 7 is in the hundredths place.

6 0
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