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Viefleur [7K]
3 years ago
9

AB=6CM AC= 12cm calculate the length of CD

Mathematics
2 answers:
Brrunno [24]3 years ago
7 0

AB=6cm AC=12cm

AC² = AB + BC²

12² = 6² + CB²

CB² = 12² - 6²

CB² = 144 - 36

CB² = 108

CB = √ 108 cm.

sin 55° = CB / CD

0.81915 = √108 / CD

CD = 10.392 / 0.81915

CD = 12.686 cm

Ket [755]3 years ago
3 0

Answer:

Step-by-step explanation:

This was a question on mathswatch, so I’ve done this.

You need to round to 3 significant numbers

AB=6cm AC=12cm

AC² = AB + BC²

12² = 6² + CB²

CB² = 12² - 6²

CB² = 144 - 36

CB² = 108

CB = √ 108 cm.

sin 55° = CB / CD

0.81915 = √108 / CD

CD = 10.392 / 0.81915

CD = 12.686 cm

CD = 12.7 cm

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Write the equation in vertex form and then find the vertex, focus, and directrix of a parabola with equation x=y^2+18y-2
kakasveta [241]

Answer:

Part 1) The vertex is the point (-83,-9)

Part 2) The focus is the point (-82.75,-9)

Part 3) The directrix is x=-83.25

Step-by-step explanation:

step 1

Find the vertex

we know that

The equation of a horizontal parabola in the standard form is equal to

(y - k)^{2}=4p(x - h)

where

p≠ 0.

(h,k) is the vertex

(h + p, k) is the focus

x=h-p is the directrix

In this problem we have

x=y^{2} +18y-2

Convert to standard form

x+2=y^{2} +18y

x+2+81=y^{2} +18y+81

x+83=(y+9)^{2}

so

This is a horizontal parabola open to the right

(h,k) is the point (-83,-9)

so

The vertex is the point (-83,-9)

step 2

we have

x+83=(y+9)^{2}

<em>Find the value of p</em>

4p=1

p=1/4

<em>Find the focus</em>

(h + p, k) is the focus

substitute

(-83+1/4,-9)

The focus is the point (-82.75,-9)

step 3

Find the directrix

The directrix of a horizontal parabola is

x=h-p

substitute

x=-83-1/4

x=-83.25

6 0
3 years ago
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