All categories

3 years ago

AB=6CM AC= 12cm calculate the length of CD

Mathematics

2 answers:

Brrunno [24]3 years ago

7 0

AB=6cm AC=12cm

AC² = AB + BC²

12² = 6² + CB²

CB² = 12² - 6²

CB² = 144 - 36

CB² = 108

CB = √ 108 cm.

sin 55° = CB / CD

0.81915 = √108 / CD

CD = 10.392 / 0.81915

CD = 12.686 cm

Ket [755]3 years ago

3 0

Answer:

Step-by-step explanation:

This was a question on mathswatch, so I’ve done this.

You need to round to 3 significant numbers

AB=6cm AC=12cm

AC² = AB + BC²

12² = 6² + CB²

CB² = 12² - 6²

CB² = 144 - 36

CB² = 108

CB = √ 108 cm.

sin 55° = CB / CD

0.81915 = √108 / CD

CD = 10.392 / 0.81915

CD = 12.686 cm

CD = 12.7 cm

You might be interested in

5 + 3x - 2 for in the simplest form

emmasim [6.3K]

Answer:

3x +3

Step-by-step explanation:

5 + 3x - 2

Combine like terms

3x +5-2

3x +3

8 0

3 years ago

Read 2 more answers

Find the value of the expression 2x3 + 3y2 − 17 when x = 3 and y = 4. 26 85 943 1,927

Jet001 [13]

Answer:

Step-by-step explanation:

2x^3 + 3y^2 − 17

2(3)^3 + 3(4)^2 − 17

2*27 + 3*16 -17

54 + 48 -17 = 85

4 0

3 years ago

Read 2 more answers

Increase the number 120 by 70%

Karo-lina-s [1.5K]

Multiply 120 by .7 then take the product and add it to 120.

3 0

3 years ago

Shortest distance from the base of parallelogram to its opposite side is the

Wittaler [7]

I believe the answer is height

3 0

4 years ago

Kyle received the following course grades for 10 (three-credit) courses during his freshman year:

timofeeve [1]

Answer:

(a) The average grade point is 2.5.

(b) The relative frequency table is show below.

Step-by-step explanation:

The given data set is

4, 4, 4, 3, 3, 3, 1, 1, 1, 1

(a)

The average grade point is

$Average=\frac{\sum x}{n}$

$Average=\frac{4+4+4+3+3+3+1+1+1+1}{10}$

$Average=2.5$

Therefore the average grade point is 2.5.

(b)

$\text{Relative frequency}=\frac{\text{Frequency of number}}{\text{Total frequency}}$

The relative frequency table is show below:

x f Relative frequency

4 3 $\frac{3}{10}=0.3$

3 3 $\frac{3}{10}=0.3$

1 4 $\frac{4}{10}=0.4$

(c)

Mean of the relative frequency distribution is

$Average=\frac{0.3+0.3+0.4}{3}$

$Average=0.3333$

Therefore the mean of the relative frequency distribution is 0.3333.

4 0

3 years ago