How do i factor the following expression 16z^2-25

2 answers:

7 0

This is the same as $a^{2}- b^{2}$
it factorizes into (a-b)(a+b)
so root of 16z^2 would be 4z
root of 25 would be 5
so factorizing it will give you
(4z - 5)(4z + 5)

mart [117]3 years ago

3 0

16z^2-25=0
(4z)^2-(5)^2=0
This is in the form of a^2-b^2=(a+b)(a-b)
(4z)^2-(5)^2=(4z+5)((4z-5)

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