Question

How do i factor the following expression 16z^2-25

Answer 1

This is the same as $a^{2}- b^{2}$
it factorizes into (a-b)(a+b)
so root of 16z^2 would be 4z
root of 25 would be 5
so factorizing it will give you
(4z - 5)(4z + 5)

Answer 2

16z^2-25=0
(4z)^2-(5)^2=0
This is in the form of a^2-b^2=(a+b)(a-b)
(4z)^2-(5)^2=(4z+5)((4z-5)