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kari74 [83]
3 years ago
6

Complete the statement. 8,500 cm = _____ m correct=brainliest

Mathematics
2 answers:
OleMash [197]3 years ago
8 0

Answer:

85

Step-by-step explanation:

andrew-mc [135]3 years ago
4 0

Answer:

85 m

Step-by-step explanation:

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359,352,345 38th term
bulgar [2K]

Answer:

38th term of AP is 100

Step-by-step explanation:

à+n-1×d

359+38-1×-7

359+(-259)

100

5 0
3 years ago
A car dealership earns a portion of its profit on the accessories sold with a car. The dealer sold a Toyota Camry loaded with ac
lina2011 [118]

Answer:

y = 2666.67

Step-by-step explanation:

Well to solve this we can make a system of equations.

x = cost of car alone

y = cost of accesories,

\left \{ {{x+y=24000} \atop {x=8y}} \right.

So now we plug in 8y for x in x + y = 24000.

(8y) + y = 24000

9y = 24000

Divide both sides by 9

y = 2666.666666

or 2666.67 rounded to the nearest hundredth.

Now that we have y we can plug that in for y in x=8y.

x = 8(2.666.67)

x = 21,333.33 rounded to the nearest hundredth.

<em>Thus,</em>

<em>accessories "y" cost around 2666.67.</em>

<em />

<em>Hope this helps :)</em>

6 0
3 years ago
Read 2 more answers
What is the length of the unknown leg of the right​ triangle?
cluponka [151]

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length of unknown side is 59

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2 years ago
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Solve for x. Enter the solutions from least to greatest.
worty [1.4K]

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less than 7, greater than 1

Step-by-step explanation:

8 0
3 years ago
Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x^3 − 3x^2 − 9x + 4 (a) Find the interval on which
Eduardwww [97]

Answer:

(-∞, -1 )∪(3, ∞)

Step-by-step explanation:

Given function,

f(x) = x^3 - 3x^2 - 9x + 4

Differentiating with respect to x,

f'(x)=3x^2-6x-9

For increasing or decreasing,

f'(x) = 0

\implies 3x^2-6x-9=0

By quadratic formula,

x=\frac{-(-6)\pm \sqrt{(-6)^2-4\times 3\times -9}}{6}

=\frac{ 6\pm \sqrt{36+108}}{6}

=\frac{6\pm \sqrt{144}}{6}

\frac{6\pm 12}{6}

\implies x = 3\text{ or } x = -1

In interval (-∞, -1 ), f'(x) = positive,

⇒ f(x) is increasing on (-∞, -1 ),

In interval (-1, 3), f'(x) = negative,

⇒ f(x) is decreasing on (-1, 3),

In interval (3, ∞), f'(x) = positive,

⇒ f(x) is increasing on (3, ∞),

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