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Olenka [21]
3 years ago
5

Factorise: 3x3-3x2y+xy2-x2y

Mathematics
1 answer:
qaws [65]3 years ago
5 0

3x^3-3x^2y+xy^2-x^2y

All terms have an x in them, so you factor that out first to get

x(3x^2 -4xy+y^2)

Now the 2nd degree equation will be of the form (3x- ... y)(x- ... y) and by just trying you find that the ... is just 1. So the factorization is:

x(3x - y)(x - y)

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