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3 years ago

How to solve y for the equation 6y+x=8

Mathematics

2 answers:

IgorC [24]3 years ago

7 0

y=4/3-x/6

Step-by-step explanation:

6y/6+x/6=8/6

y+x/6=4/3

-x/6 -x/6

y=4/3-x/6

yan [13]3 years ago

5 0

$\text{Solve for y:}\\\\6y+x=8\\\\\text{Subtract x from both sides}\\\\6y=-x+8\\\\\text{Divide both sides by 6}\\\\y=-\frac{1}{6}x+\frac{8}{6}\\\\\text{Simplify}\,\,\frac{8}{6}\\\\\boxed{y=-\frac{1}{6}x+\frac{4}{3}}$

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4/6 x what equals 8/6

Sidana [21]

Answer: 4/6

1. Subtract 8/6 by 4/6.

8/6 - 4/6 = 4/6

4/6 + 4/6 = 8 is the same as:

4 + 4 = 8

<em>Notice: You don't change the denominator if your adding or subtracting.</em>

<em />

<h2>Final answer: 4/6. </h2>

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2 years ago

I have k quarters, five less quarters than nickels and one more than twice as many dimes as quarters. Find the value of the coin

Alenkinab [10]

Answer:

(35k + 20) cents

Step-by-step explanation:

First of all, let us have the value of each unit:

1 quarter = 25 cents

1 nickel = 5 cents

1 dime = 10 cents

Given that number of quarter = k

Quarters are 5 lesser than Nickels, so number of nickels = k+5

One more than twice as many dimes as quarters:

k = 2 $\times$ Number of Dimes + 1

So, number of dimes = $\frac{1}{2}(k-1)$

Value of quarters = $25 \times k$ cents

Value of nickels = $5 \times (k+5) = (5k+25)\ cents$

Value of dimes = $\frac{1}{2}(k-1) \times 10 = (5k-5)\ cents$

So, total value of coins =

$25k + 5k +25 +5k-5\\\Rightarrow (35k+20)\ cents$

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3 years ago

Read 2 more answers

3. Find the number which is 32,586 more than 87,65,432.

sweet [91]

Answer:

3. 8,798,018

4. 4,782,125

5. 156,432,332

6. 4,581,865

7. 4,594,375

8. 3,672,050

9. 7,272,925

10. 3,979,150

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2 years ago

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The answer is 0.5333E

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2 years ago

Solve the decay equation y' = -ky using the integrating factors method. Show work

Alex777 [14]

Answer:

$y=\frac{c}{e^{kx}}$

Step-by-step explanation:

$\frac{\mathrm{d} y}{\mathrm{d} x} =-ky$

$\frac{\mathrm{d} y}{\mathrm{d} x} +ky=0$

comparing with equation

$\frac{\mathrm{d} y}{\mathrm{d} x} + Py=Q(x)$

$I.F.= e^{\int P dx}$

$I.F.= e^{\int k dx}$

$I.F.= e^{kx}$

$y=\frac{1}{I.F.} ( \int {Q(x)} dx +c)$

$y=\frac{1}{e^{kx}} ( \int {0} dx +c)$

$y=\frac{c}{e^{kx}}$

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3 years ago