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True [87]
3 years ago
12

What is Arithmetic Series

Mathematics
1 answer:
klio [65]3 years ago
4 0

Answer:

I am pretty sure it is when you have a sequence of numbers that you are subtracting or adding from by the same constant over and over

Step-by-step explanation:

an=a1+(n-1)d

d=common difference

an= the nth term in the sequence

a1 first term in the sequence. (Usually you can plug in 1, as the n, and work from there)

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Calculate 1.6 x 0.215 show your reasoning
WITCHER [35]

Answer:

0.344

Step-by-step explanation:

6 0
2 years ago
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In February, Alec had 1,562 visitors to his website. In March, he had 1,310 visitors to his website. What is the percentage decr
tigry1 [53]

Answer:

16.1% is the percentage decrease.

Step-by-step explanation:

We are given the following in the question:

Visitors in February = 1,562

Visitors in march = 1,310

We have to find the percentage decrease of the number of visitors to Alec's website from February to March.

Percentage decrease =

=\dfrac{\text{Change}}{\text{Original}}\times 100\%\\\\=\dfrac{1562-1310}{1562}\times 100\%\\\\=\dfrac{252}{1562}\times 100\% = 16.1\%

Thus, 16.1% is the percentage decrease in the number of visitors to Alec's website from February to March.

6 0
3 years ago
If anyone can solve this quickly I will give brainly
Nataly [62]

Answer:

m∠BFE  = 171º

BE = 219º

Step-by-step explanation:

∠BFE is supplementary to ∠EFC

m∠BFE  = 180 - 9

m∠BFE  = 171º

--------------------------

The angle between two chords is equal to half the sum of the intercepted arcs:

∠BFE = (DC + BE)2

171 = (123 + BE)/2

342 = 123 + BE

219º = BE

6 0
3 years ago
A mixture of purple paint contains 6 teaspoons of red paint and 15 teaspoons of blue paint. To make the same shade of purple pai
xeze [42]

Answer:

djekodoxlsksdiosoxx

3 0
3 years ago
Common factors of 8xy⁴,6x²y,10x²y²​
Citrus2011 [14]

Answer:

2^{3}×5×3×x^{2}×y^{4}

Step-by-step explanation:

8xy^{4}= 2^{3}×x×y^{4}

6x^{2} y= 2×3×x^{2}×y^{}

10x^{2} y^{2} = 2×5×x^{2}×y^{2}

2^{3}×5×3×x^{2}×y^{4}

4 0
2 years ago
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