How can we eliminate an imaginary from the denominator? Simplify 2/(3+5i) to demonstrate.
1 answer:
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Answer:
Step-by-step explanation:
He already has songs = 41
Since we are given that he purchase four songs every week .
So, in first week he purchase songs = 4
Initially he already has 41 songs
So, total songs after 1 week =
After 2 weeks he will have songs =
This forms an arithmetic sequence : 41,45,49......
Formula of nth term in A.P. :
a = first term = 41
d = common difference = 45-41=49-45=4
Since we are required to find the new songs after110 weeks
So, n =110
Substituting values :
Thus Option A is correct.
Answer:
849 items.
Step-by-step explanation:
Given that the profit C (in thousands of dollars) for x thousands of items related as
As the profit is $14,000 for producing 2000 items, so
C= 14 thousand dollars and
x= 2 thousand items.
Putting C= 14 in the equation ( we have),
Now, x=2 is one of the solutions to the equation (ii), so (x-2) is a factor of the equation (ii), we have
We have the given solution for x-2=0, so sloving -5x^2-4x+7=0 for other solutions.
As the number of items cant be negative, so x= 0.849 thousand is the other number of items.
Hence, the other number of items for the same profit is 849 items.
Answer:
Option B that is (2,6) is correct
Explanation:
We have been given with system of equations
and
Here, we will substitute the value of in
We will get
Further simplification we will get to
Hence, the value of
And now, substituting the value in
we will get
.
Therefore, option B is correct.