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3 years ago

Find the missing length of the triangles it’s OK if you can only do one

Mathematics

1 answer:

sammy [17]3 years ago

8 0

Answer:

5) 9

6) 11 2/3

Step-by-step explanation:

Use the Pythagorean Theorem.

5) a²+5.6²=10.6²

a²+31.36=112.36

a²=81

a=√81

a=9

6) a²+4²=12.3333²

a²+16=152.11111

a²=152.11111-16

a²=136.1111

a=√136.1111=11.6666

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Need help on this I don't get it

Nataly [62]

Step-by-step explanation:

It is not a solution because the point falls outside the shaded region, if you were to plugin the point it would return a false statement

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2 years ago

Prove : sin²θ + cos²θ = 1 thankyou ~

Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

$\sf\longrightarrow sin^2\theta + cos^2\theta = 1$

Imagine a right angled triangle with one of its acute angle as $\theta$ .

The side opposite to this angle will be perpendicular .
Also we know that ,

$\sf\longrightarrow sin\theta =\dfrac{p}{h} \\$

$\sf\longrightarrow cos\theta =\dfrac{b}{h}$

And by Pythagoras theorem ,

$\sf\longrightarrow h^2 = p^2+b^2 \dots (i)$

Where the symbols have their usual meaning.

Now , taking LHS ,

$\sf\longrightarrow sin^2\theta +cos^2\theta$

Substituting the respective values,

$\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\$

$\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\$

$\sf\longrightarrow \dfrac{p^2+b^2}{h^2}$

From equation (i) ,

$\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\$

$\sf\longrightarrow \bf 1 = RHS$

Since LHS = RHS ,

Hence Proved !

I hope this helps.

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2 years ago

What type of triangle has side lengths of 23, 24, and 24?

Hatshy [7]

B. I think....... :)

6 0

3 years ago

Read 2 more answers

Pls helpppppp thanks!!!!!!! :)

Lena [83]

Answer:

If i did this right the answer would be 69

I converted the inches to feet (might be my first mistake)

so i get 2.5 X 1 X 1 to get 2.5

i then multiply that by 62.4 to get 156

then 225-156 = 69

Step-by-step explanation:

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3 years ago

Mulitply (2-2)(3x+4) using distributive property

Sati [7]

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3 years ago