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3 years ago

Which of the following sets of numbers could be the lengths of the sides of a triangle?

1 answer:

7 0

B. 3ft, 4ft, 5ft

Pythagoras' Theorem where the square of the two smaller sides added together equals the square of the hypotenuse. If the two smaller sides are 3 and 4 then the hypotenuse is always going to be 5

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Is -75 greater or less than -90

vladimir2022 [97]

Answer
Greater
Explanation

6 0

3 years ago

What are three equivalent fractions to 4/11

kkurt [141]

4/11 (2/2) = 8/22

4/11 (3/3) = 12/33

4/11 (4/4) = 16/44

5 0

3 years ago

Read 2 more answers

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

4 years ago

X+1=5 wat is this pls answer bozo

slamgirl [31]

X = 4. You subtract 1 from both sidea

5 0

3 years ago

Read 2 more answers

Which expressions are equivalent to the given expression?

liraira [26]

$2\sqrt{10}$ is equivalent to the expression $\sqrt{40}$

entire to mixed radical:

$\sqrt{40} \\\sqrt{4\ x\ 10} \\2\sqrt{10}$

decimal value:

$2\sqrt{10}=6.32....\\\sqrt{40}=6.32...$

3 0

2 years ago