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3 years ago

A basketball player made 63 out of 100 attempted free throws.what percent of free throws did the player make

Mathematics

2 answers:

Savatey [412]3 years ago

8 0

Answer:

63%

Step-by-step explanation:

lutik1710 [3]3 years ago

3 0

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

Let's see...

Step-by-step explanation:

<u>per</u><em>cent</em> means <u>per</u> <em>hundred</em> or <u>out of</u> <em>one hundred</em>

<em />

[I added the underline and italics to help show which means which].

So, that being said, how do we find our percentage?

63 is <u>out of</u> <em>one hundred</em>. So what is our answer?

<h3>Our answer is 63%</h3>

I hope this helps!

- sincerelynini

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Does anyone know the answer to this?

Savatey [412]

Answer:

numbers of tables on the y axis and the money earned on the x axis

Step-by-step explanation:

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3 years ago

You pawn a guitar and receive $880. One month later, you get the guitar back by paying $1250. If this is simple interest, then w

Lemur [1.5K]

Interest=1250-880=370
I=PRT
P=principal
r=rate in deicmal
t=time in years

1 month so t=1/12
P=880
I=370

370=880*r*1/12
370=220/3r
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3 years ago

Pls help I am so lost

Anni [7]

Answer:

4 would be 36

Step-by-step explanation:

PEMDAS! <3

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3 years ago

Read 2 more answers

Assuming that the equation defines x and y implicitly as differentiable functions xequalsf(t), yequalsg(t), find the slope of

Doss [256]

Answer:

$\dfrac{dx}{dt} = -8,\dfrac{dy}{dt} = 1/8\\$

Hence, the slope , $\dfrac{dy}{dx} = \dfrac{-1}{64}$

Step-by-step explanation:

We need to find the slope, i.e. $\dfrac{dy}{dx}$ .

and all the functions are in terms of $t$ .

So this looks like a job for the 'chain rule', we can write:

$\dfrac{dy}{dx} = \dfrac{dy}{dt} .\dfrac{dt}{dx} -Eq(A)$

Given the functions

$x = f(t)\\y = g(t)\\$

and

$x^3 +4t^2 = 37 -Eq(B)\\2y^3 - 2t^2 = 110 - Eq(C)$

we can differentiate them both w.r.t to $t$

first we'll derivate Eq(B) to find dx/dt

$x^3 +4t^2 = 37\\3x^2\frac{dx}{dt} + 8t = 0\\\dfrac{dx}{dt} = \dfrac{-8t}{3x^2}\\$

we can also rearrange Eq(B) to find x in terms of t , $x = (37 - 4t^2)^{1/3}$ . This is done so that $\frac{dx}{dt}$ is only in terms of t.

$\dfrac{dx}{dt} = \dfrac{-8t}{3(37 - 4t^2)^{2/3}}\\$

we can find the value of this derivative using t = 3, and plug that value in Eq(A).

$\dfrac{dx}{dt} = \dfrac{-8t}{3(37 - 4t^2)^{2/3}}\\\dfrac{dx}{dt} = \dfrac{-8(3)}{3(37 - 4(3)^2)^{2/3}}\\\dfrac{dx}{dt} = -8$

now let's differentiate Eq(C) to find dy/dt

$2y^3 - 2t^2 = 110\\6y^2\frac{dy}{dt} -4t = 0\\\dfrac{dy}{dt} = \dfrac{4t}{6y^2}$

rearrange Eq(C), to find y in terms of t, that is $y = \left(\dfrac{110 + 2t^2}{2}\right)^{1/3}$ . This is done so that we can replace y in $\frac{dy}{dt}$ to make only in terms of t

$\dfrac{dy}{dt} = \dfrac{4t}{6y^2}\\\dfrac{dy}{dt}=\dfrac{4t}{6\left(\dfrac{110 + 2t^2}{2}\right)^{2/3}}\\$

we can find the value of this derivative using t = 3, and plug that value in Eq(A).

$\dfrac{dy}{dt} = \dfrac{4(3)}{6\left(\dfrac{110 + 2(3)^2}{2}\right)^{2/3}}\\\dfrac{dy}{dt} = \dfrac{1}{8}$

Finally we can plug all of our values in Eq(A)

but remember when plugging in the values that $\frac{dy}{dt}$ is being multiplied with $\frac{dt}{dx}$ and NOT $\frac{dx}{dt}$ , so we have to use the reciprocal!

$\dfrac{dy}{dx} = \dfrac{dy}{dt} .\dfrac{dt}{dx}\\\dfrac{dy}{dx} = \dfrac{1}{8}.\dfrac{1}{-8} \\\dfrac{dy}{dx} = \dfrac{-1}{64}$

our slope is equal to $\dfrac{-1}{64}$

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3 years ago

What is the function graphed below?

Ilya [14]

Answer:

Your correct answer would be option 2. y = IxI -1 Please vote Brainliest!

Step-by-step explanation:

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