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WARRIOR [948]
3 years ago
8

Which inequality comparing two of the expressions below is true when 0.5

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer:

<u>Option C</u>

Step-by-step explanation:

Given 0.5≤ x ≤ 0.7

According to the range of x, we will check which option is true

Let x = 0.6

A. \frac{x}{3} > \sqrt{x}

If x = 0.6

∴0.6/3  >  √0.6 ⇒  0.2 > 0.77  ⇒ <u>Wrong inequality </u>

B. x³ > 1/x

If x = 0.6

∴ 0.6³ > 1/0.6  ⇒ 0.216 > 1.667  ⇒ <u>Wrong inequality </u>

<u></u>

C. √x > x³

If x = 0.6

∴ √0.6 > 0.6³  ⇒ 0.77 > 0.216  ⇒ <u>True inequality </u>

D. (x/3) > (1/x)

If x = 0.6

∴  0.6/3  >  1/0.6   ⇒ 0.2  > 1.667  ⇒<u> Wrong inequality </u>

<u>So, The true inequality is option C</u>

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Ghella [55]

Let the four consecutive integers be

x , x+1, x+2, x+3

ATQ, Their sum is 18

\sf \: x + x + 1 + x + 2 + x + 3 = 18

\sf \: 4x + 1 + 2 + 3 = 18

\sf4x + 6 = 18

\sf4x = 18 - 6

\sf4x = 12

\boxed{ \mathfrak{x = 3}}

<h3>Now,</h3>

  • 1st number = x = 3
  • 2nd number = x+1 = 3+1 = 4
  • 3rd number = x+2 = 3+2 = 5
  • 4th number = x+3 = 3+3 = 6

<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

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29.) This is simply interpreting the linear function.
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