Answer:
<em>6</em><em>0</em><em>0</em><em>-</em><em>1</em><em>2</em><em>5</em><em>0</em><em> </em><em> </em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>hop</em><em>e</em><em> it's</em><em> helped</em><em> you</em>
Answer:
The genotypes of the rooster and the chicken are homozygous and that of their offspring is heterozygous.
This case is called codominance, where the offspring receives an allele from each parent, from the rooster and the hen, because there is codominance, so neither allele is recessive and the phenotype of both alleles is expressed so the phenotype of the offspring is checkered.
We can say then that the chicken and the rooster have equal strength between their alleles. in the cases of codominance the laws of mendel do not apply.
<span>heterozygous / homozygous refers to whether both alleles for a gene are the same. The organism is homozygous if both alleles are the same - that is, either both are dominant or both are recessive. The organism is heterozygous if the alleles are different - that is, if one allele is dominant and the other allele is recessive..
the answer to the questions is A. </span><span>One parent was heterozygous for eye color and the other was homozygous with red eyes.</span>
