Question

Using point slope form write the equation of the line that passes through the point (-1/2, 1/2) and has a slope of -1

Answer 1

Answer:

y = -x

Step-by-step explanation:

Given in the question,

co-ordinate(-1/2 , 1/2)

gradient of the line = -1

Standard equation form of a straight line

y - y1 = m(x - x1)

here y1 = 1/2

        x1 = -1/2

        m = -1

Plug values in the equation

y - 1/2 = -1(x + 1/2)

y -1/2 = -x - 1/2

y = -x

Answer 2

Answer: $y-\frac{1}{2}=-(x+\frac{1}{2})$

Step-by-step explanation:

The point-slope form of the equation of the line is:

$y-y_1=m(x-x_1)$

Where "m" is the slope of the line and $(x_1,y_1)$ is a point of the line.

You know the value of the slope and you also know a point of the line, then you need to substitute values into $y-y_1=m(x-x_1)$.

Therefore, you get that the equation of this line in  point-slope form is:

$y-\frac{1}{2}=-1(x-(-\frac{1}{2})\\\\y-\frac{1}{2}=-(x+\frac{1}{2})$