Answer:
Discount percentage is 16.4% for the customers who purchase 6- coupon book .
Step-by-step explanation:
Formula
As given
Your station charges $15.95 for an oil change.
Original charge of the oil change for 6 times = 6 × Original charge for oil change .
= 6 × 15.95
= $ 95.7
As a promotion you sell six coupons for oil changes for $80.
Discount = Original charge of the oil change for 6 times - Charge by six coupons for oil changes .
= $95.7 - $80
= $ 15.7
Putting all the values in the above
Discount percentage = 16.4%
Therefore the discount percentage is 16.4% for the customers who purchase 6- coupon book .
Answer:
The answer is B. 38.25
Step-by-step explanation:
4.5*8.5
Answer:
4/3
Step-by-step explanation:
The tangent of any angle (θ) in standard position that has point (x, y) on its terminal ray is ...
tan(θ) = y/x
__
For the given point on the terminal side, the tangent is ...
tan(θ) = (-4)/(-3) = 4/3
_____
<em>Additional comment</em>
There are several ways this can be explained. One of them makes use of the relation between rectangular and polar coordinates:
(x, y) = (r·cos(θ), r·sin(θ))
Then the ratio y/x is ...
y/x = (r·sin(θ))/(r·cos(θ)) = sin(θ)/cos(θ) = tan(θ)
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
