OK...... your answer would be
- 10y^2 - 26y + 1/y
H0P3 It H3LPS :)
Answer:
(3y - 2)(2y - 7)
Step-by-step explanation:
To factorise the quadratic
Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term
Product = 6 × 14 = 84 and sum = - 25
The required factors are - 4 and - 21
Use these factors to split the y- term
6y² - 4y - 21y + 14 ( factor the first/second and third/fourth terms )
2y(3y - 2) - 7(3y - 2) ← factor out (3y - 2) from each term
= (3y - 2)(2y - 7) ← in factored form
What do you need help with
Step-by-step explanation:
that is
sum(2^r) for r=1 to n, plus sum(1/2) for r=1 to n.
and that is
sum(2^r) + n/2 for r=1 to n.
2^r is a geometric sequence with 2 being the common ratio (every new term is created by multiplying the previous term by 2).
and since r is starting at 1, the first term a1 = 2.
the formula for the sum of a finite geometric sequence is
Sn = a1×(1 - r^n) / (1 - r)
with r being the common ratio .
so, in our case
Sn = 2×(1 - 2^n) / (1 - 2)
Sn = (2 - 2^(n+1)) / -1 = 2^(n+1) - 2
and so, in total we get
2^(n+1) - 2 + n/2 = 2^(n+1) + (n - 4)/2
Answer:
x = - 5
Step-by-step explanation:
3x - 3 - 6x = 12
group like terms
3x - 6x - 3 = 12
add similar elements
- 3x - 3 = 12
add 3 to both sides
- 3x - 3 + 3 = 12 + 3
simplify
- 3x = 15
divide both sides by 3
- 3x / 5 = 15 / - 3
simplify
x = - 5
