Step-by-step explanation:
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To find the root, replace y with 0
X^2-12x+35=0
A=1 B=-12 C=35
B^2-4ac=(-12)^2 -4(1)(35)
=144 -140
=4
x=(-b+/- square root of b^2 -4ac) /over/ (2a)
Plug in the numbers
x=-(-12) sqr (-12)^2 4(1)(35) / (2)(1)
X=12 +/-sqr 4 / 2
Positive outcome
x=12 + sqr 4 / 2
x=12+2/2
x=7 <— this one
Negative outcome
x=12-2i/2
x=6-i
Vertex: (6,-1)
Answer:
Center: (-3,-2)
Radius: √6
The graph is attached.
Step-by-step explanation:
The equation of the circle has the form:

Where (h,k) is the point of the center of the circle and r is the radius of the circle.
The equation given in the problem is

Therefore:
h=-3
k=-2
The center is at (-3,-2)
And the radius is:

Then, you can graph it has you can see in the image attached.
-8, -48, -288
or
-8, -4/3, -2/9