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Vlada [557]
3 years ago
11

One way to classify organisms is by analyzing their genetic information to determine where they belong within a phylogenetic tre

e or cladogram. Which of the following best describes a complication of classifying bacteria based on genetic information?
A.) The DNA in one species of bacteria can be exchanged with an unlike species of bacteria.. .
B.) The DNA mutation rate of bacteria cannot be tracked, unlike other organisms.. .
C.) The DNA of bacteria cannot be distinguished from the DNA of organisms they may use as a host.. .
D.) The DNA of bacteria is not made of the same nucleic acids as o
Biology
2 answers:
Elodia [21]3 years ago
7 0
"The DNA in one species of bacteria can be exchanged with an unlike species of bacteria" is the one among the following that <span>best describes a complication of classifying bacteria based on genetic information. The correct option among all the options that are given in the question is the first option or option "A".</span>
Iteru [2.4K]3 years ago
4 0

The correct answer is option A) The DNA in one species of bacteria can be exchanged with an unlike species of bacteria.

Phylogenetic trees are very helpful in tracing lineages and categorizing the animals on the basis of their genetic makeup so that evolutionary relationships between organisms may be established. The DNA of one species of bacteria can be exchanged with an unlike species of bacteria by a process known as horizontal gene transfer. Horizontal gene transfer (HGT) is also known as lateral gene transfer. In HGT, the transfer of DNA does not occur through lateral gene transfer like in case of transfer of DNA from parents to progenies. We consider parents as the most closely related to the progenies because their DNA is more or less same as that of progenies. But in HGT, a bacteria can transfer its genes to a totally unrelated strain of bacteria  via conjugation, transformation or transduction. Since the DNA is being incorporated to an unrelated strain, in a phylogenetic tree the unrelated strain will show up as a related strain to the bacteria from which is has received the DNA through HGT even though it is unrelated. This is how it will create hurdle in tracing lineages and classifying bacteria.

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87.5% of the trimers in the cell will be inactive.

Explanation:

A monomer is a single subunit. Look at an easy comparison. If a monomer is a ball. For the protein to be functional, it needs to be a trimer .A trimer = 3 monomers joined / bound together with bonds. Therefore, if a monomer is a ball, we need 3 balls, we attach it together and that is the primer . if one ball becomes missing, that protein won't work .

In chemistry, a trimer is regarded as three molecules or ions of the same substance (that is, same type) which are associated together .

Double negative : Each gene has 2 alleles. So, for a positive protein, both allele needs to be same, let's say + means on. So for a x protein , if it's x+/x+ it means the protein is homozygous and active. If for some mutation, it's x+/x- , it's a heterozygous protein. Double negative means when it is x-/x- and this means the protein has lost is function . It's not functional at all.

The heterozygous cell will form one or more subunits has the mutant structure when the gene is expressed. From the question if there is a mutation in dominant negative allele, it will cause the inactivation of one trimer resulting in 87.5% inactive trimers for a heterozygous individual.

There are 87.5 % percent of the trimers present in the cell which will be inactive for a heterozygous individual, If at least one of the subunits has the mutant structure.

The probability for each individual subunit to be a mutant is 1/2

Gene codes for a protein that forms trimer so the percentage of the trimers present in the heterozygous individual is third power of 1/2 =1/8

1/8=0.125 will be active.

1- 0.125 will be inactive.

=0.875 will be inactive.

0.875 × 100= 87.5%

Therefore 87.5% will be inactive.

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