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KonstantinChe [14]
2 years ago
7

Line segment QR is dilated to create line segment Q'R' using the dilation rule DT,1.5. Point T is the center of dilation. Line s

egment Q R is dilated to create line segment Q prime R prime. The length of R T is 6 and the length of R prime R is y. What is y, the distance between points R and R'?
Mathematics
2 answers:
velikii [3]2 years ago
5 0

Answer:

y= 3

Step-by-step explanation:

Given

RT = 6

k = 1.5 --- dilation ratio

See attachment

Required

Determine length, y

First, we calculate length R'T.

Since point T is the center of dilation, then:

R'T = k * RT

Substitute known values

R'T = 1.5 * 6

R'T = 9

y is between R'T and RT;

So:

y = R'T - RT\\

y = 9 -6

y= 3

nalin [4]2 years ago
5 0

Answer:

either 4 or 9

Step-by-step explanation:

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Orlov [11]
<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

or

Range: (2,∞+)

<h2>Why?</h2>

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

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Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

5 0
3 years ago
18. Let z = a + bi represent a general complex number. As noted in the lesson, the conjugate of z, abbreviated conj(z) or conj(a
AnnyKZ [126]

Question (18):

Answer: (A) All of the following

(I am using z^* in place of conj(z)

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2 years ago
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taurus [48]
Let's get the denominators of both fractions to be the same before moving on, aka finding the least common multiple of the denominators.

8 and 3 have a LCM of 24. So, we have to multiply 1/3 by 8 and 3/8 by 3.

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There is only 1/24 of juice left in the bottle if the remaining amount of juice has 1/3 poured out.

Hope that helped.
4 0
3 years ago
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Answer:

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ratio and proportion

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Answer:

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Step-by-step explanation:

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