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Elza [17]
3 years ago
12

X-4y=7 -6x-3y=12 how do i solve by substitution​

Mathematics
1 answer:
Dafna1 [17]3 years ago
3 0

Answer:

x = 15

y = 2

Step-by-step explanation:

X-4y=7 | ×6 |

-6x-3y=12 | ×1 |

6x - 24y = 42

-6x - 3y = 12

___________+

27y = 54

y = 54/27

y = 2

x - 4y = 7

x - 4(2) = 7

x - 8 = 7

x = 7 + 8

x = 15

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Answer:

<span>A. The set of all ordered pairs (x,y) that are solutions to the equation

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8 0
3 years ago
The square below represents one whole.
kupik [55]

Answer:

\text{Shaded area as fraction}=\frac{81}{100}

\text{Shaded area as decimal}=0.81

\text{Shaded area as percent of the whole}=81\%

Step-by-step explanation:

Please consider the attached image as the given square.

We are asked to express the shaded area as a fraction, a decimal, and a percent of the whole.

We can see that in our figure there are 100 squares as there are 10 rows and each row contains 10 squares.

We can also see that there are 81 shaded squares out of 100 squares, so we can represent it as a fraction as:

\frac{\text{Shaded squares}}{\text{Total squares}}

\text{Shaded area as fraction}=\frac{81}{100}

To convert the shaded area into decimal, we need to divide 81 by 100.

\text{Shaded area as decimal}=0.81

To convert the shaded area into percent, we need to multiply 0.81 by 100.

\text{Shaded area as percent of the whole}=0.81\times 100\%

\text{Shaded area as percent of the whole}=81\%

7 0
3 years ago
Read 2 more answers
Directions: Divide the array in 2 smaller facts to help you fill in the
Licemer1 [7]

Answer: The answer is 56

explanation: 7*8 is the same as 8+8+8+8+8+8+8 or 7+7+7+7+7+7+7+7 and if you do the math it equals 56

8 0
3 years ago
5. What number does the model below best represent?
qaws [65]

Answer:

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Step-by-step explanation:

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3 years ago
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
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