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3 years ago

13

Dhjfhehrheheejrhhehehhhehrheehe

1 answer:

Ad libitum [116K]3 years ago

7 0

Answer:

(￣(ｴ)￣)ﾉ heyyyyyyyyyyyyyy

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Solve the following system of equations graphically on the set of axes below. Y=-x+1 Y=1/4x+6

Anastasy [175]

Answer:

look at the picture, i wrote in french but o think yoi could understand

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3 years ago

Find the derivative of f(x) = 4x + 7 at x = 5.(2 points)

Sveta_85 [38]

Answer:

x=4x+7=

x=5=

Step-by-step explanation:

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4 years ago

Find the common ratio of the geometric sequence:<br> 1.512, 7.56, 37.8, 189, 945, .... ...?

SVEN [57.7K]

5
To find the ratio you simply divide the value by the previous value
7.56/1.512 = 5
37.8/7.56 = 5

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3 years ago

Solve for x<br> (1/x) -2/3 = (4x)

Vadim26 [7]

The value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

Step-by-step explanation:

The equation is $\frac{1}{x}-\frac{2}{3}=4 x$

Subtracting by $4x$ on both sides,

$\frac{1}{x}-\frac{2}{3}-4 x=0$

Taking LCM,

$\frac{3-12 x^{2}-2 x}{3 x}=0$

Multiplying by 3x on both sides,

$-12 x^{2}-2 x+3=0$

Dividing by (-) on both sides,

$12 x^{2}+2 x-3=0$

Using quadratic formula, we can solve for x.

$\begin{aligned}x &=\frac{-2 \pm \sqrt{2^{2}-4 \cdot 12 \cdot(-3)}}{2 \cdot 12} \\&=\frac{-2 \pm \sqrt{4+144}}{2 \cdot 144} \\&=\frac{-2 \pm \sqrt{148}}{24} \\&=\frac{-2 \pm 2 \sqrt{37}}{24}\end{aligned}$

Taking out common term 2, we get,

$\begin{array}{l}{x=\frac{-2(1 \pm \sqrt{37})}{24}} \\{x=\frac{-1 \pm \sqrt{37}}{12}}\end{array}$

Thus, the value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

4 0

3 years ago

A box with a square base and no top is to be built with a volume of 4000 in3. find the dimensions of the box that requires the l

vekshin1

Let the length of the square base be x inches .

And the height of the box be y inch .

Volume = x*x*y

4000 = x *x *y

$y = \frac{4000}{x^2}$

S = x*x + 2xy + 2 x y

$S = x^2 + 4 xy$

$S = x^2+ 4x* \frac{4000}{x^2}$

$S = x^2 + \frac{16000}{x}$

$S ' = 2x - \frac{16000}{x^2}$

S ' =0

$2x - \frac{16000}{x^2}=0$

$2x^3 - 16000 = 0$

$x^3 = 8000$

x = 20

$y = \frac{4000}{20^2} = \frac{4000}{400} = 10$

6 0

3 years ago