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AfilCa [17]
4 years ago
6

(-8ab+7a-5)-(-7ab+2) find the difference

Mathematics
2 answers:
Marat540 [252]4 years ago
8 0
-8ab + 7a - 5 - (-7ab + 2)....distribute through the parenthesis
-8ab + 7a - 5 + 7ab - 2....combine like terms
-ab + 7a - 7 <===

Degger [83]4 years ago
5 0
(-8ab+7a-5)-(-7ab+2) 

Solving an equation means finding a value of a variable that make the equation true. This value is called the solution of the equation. <span>A mathematical equation is just like a balanced equation. </span><span>Both sides of the equation should be equal at all times. Whatever we do to one side, has to be done on the opposite side. 
</span>
-8ab+7a-5+7ab-2&#10;&#10; &#10; 

&#10;(-8ab+7ab)+7a-5-2&#10; &#10;   Gather \ like \ terms 

-ab+7a-5-2&#10;&#10; &#10; 

-ab+7a-7&#10;&#10; &#10;
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g An urn contains 10 balls: 4 red and 6 blue. A second urn contains 16 red balls and an unknown number of blue balls. A single b
Fed [463]

Answer:

Therefore the of blue in the second urn is 4.

Step-by-step explanation:

Let second urn contain x number of blue ball .

Urn            Red Ball          Blue Ball         Total Ball

1                       4                       6                      10

2                      16                       x                    16+x

Getting a red ball from first urn is P(R_1)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}    =\frac{4}{10}

Getting a blue ball from first urn is P(B_1)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}} =\frac {6}{10}

Getting a red ball from second urn is P(R_2)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}    =\frac{16}{16+x}

Getting a blue ball from second urn is P(B_2)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}} =\frac {x}{16+x}

Getting two red balls from first and second urn is =\frac{4}{10}\times \frac{16}{16+x}

                                                                                  =\frac{32}{5(16+x)}

Getting two blue balls from first and second urn is =\frac{6}{10}\times \frac{x}{16+x}

                                                                                  =\frac{3x}{5(16+x)}

The probability that both balls are the same in color is =\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}

Given that the probability that both balls are the same in color is 0.44.

According to the problem,

\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}=0.44

\Rightarrow \frac{32+3x}{5(16+x)} =0.44

\Rightarrow \frac {32+3x}{(80+5x)} =0.44

\Rightarrow 32+3x =0.44(80+5x)

\Rightarrow 32+3x =35.2 +2.2x

\Rightarrow 3x -2.2 x= 35.2 -32

\Rightarrow 0.8x= 3.2

\Rightarrow x = 4

Therefore the of blue in the second urn is 4.

               

5 0
3 years ago
If AB = 18 and AC = 3x +6 then x=
ryzh [129]
X would equal 4
set AB=AC
18=3x+6
minus 6 on both sides 
12=3x
divide both sides by 3
x=4
5 0
4 years ago
15 cm<br> 15 cm<br> 16 cm<br> 20 cm<br> 57 cm<br> What is the perimeter of the polygon?
Natasha2012 [34]

Answer:

C.

Step-by-step explanation:

15 x 16=240 x 2= 480

57 x 20= 1140

1140 + 480 = 1620

6 0
3 years ago
PLZ ANSWER ASAP (EASY)
Anuta_ua [19.1K]

Answer:

-4/8

Step-by-step explanation:

that's what my math says

4 0
4 years ago
Solve the given number problem.
Evgesh-ka [11]
I would say -26 because -22, -24, -26=-72
6 0
3 years ago
Read 2 more answers
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