Question

Complete the sentences to describe the function f(x) = 2x^2+16x/16x^3-x the function is discontinus at

Answer 1

Answer: the function is discontinuous at x=0

To create the extended function add f(x)=0,x=0

Step-by-step explanation:

Answer 2

Answer:

The answer is "$\bold{\frac{2(x+8)}{(4x^2- 1)(4x^2+ 1)}}$".

Step-by-step explanation:

$\to f(x) = \frac{2x^2+16x}{16x^3-x}$

            $= \frac{2x(x+8)}{x(16x^2-1)}\\\\= \frac{2(x+8)}{(16x^2-1)}\\\\= \frac{2(x+8)}{((4x)^2-(1)^2)}\\\\= \frac{2(x+8)}{(4x^2- 1)(4x^2+ 1)}$