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IRINA_888 [86]
3 years ago
6

How do I use substitution to solve

Mathematics
2 answers:
nekit [7.7K]3 years ago
4 0
<span>The method of solving "by substitution" works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.</span>
Olin [163]3 years ago
3 0
We can substitute y in the second equation with the first equation since y = y. Thesolution<span> of the linear </span>system<span> is (1, 6). You can </span>use<span> the </span>substitution<span> method even if both equations of the linear </span>system<span> are in standard form. Just begin by </span>solving<span> one of the equations for one of its variables.</span>
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Answer:

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Step-by-step explanation:

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The amount of soft drink in a bottle is a Normal random variable. Suppose that in 7% of the bottles containing this soft drink t
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Answer:

The mean is 15.93 ounces and the standard deviation is 0.29 ounces.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

7% of the bottles containing this soft drink there are less than 15.5 ounces

This means that when X = 15.5, Z has a pvalue of 0.07. So when X = 15.5, Z = -1.475.

Z = \frac{X - \mu}{\sigma}

-1.475 = \frac{15.5 - \mu}{\sigma}

15.5 - \mu = -1.475\sigma

\mu = 15.5 + 1.475\sigma

10% of them there are more than 16.3 ounces.

This means that when X = 16.3, Z has a pvalue of 1-0.1 = 0.9. So when X = 16.3, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{16.3 - \mu}{\sigma}

16.3 - \mu = 1.28\sigma

\mu = 16.3 – 1.28\sigma

From above

\mu = 15.5 + 1.475\sigma

So

15.5 + 1.475\sigma = 16.3 – 1.28\sigma

2.755\sigma = 0.8

\sigma = \frac{0.8}{2.755}

\sigma = 0.29

The mean is

\mu = 15.5 + 1.475\sigma = 15.5 + 1.475*0.29 = 15.93

The mean is 15.93 ounces and the standard deviation is 0.29 ounces.

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