The width used for the car spaces are taken as a multiples of the width of
the compact car spaces.
Correct response:
- The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>
Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.
We have;
Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)
New space design = 16·x + 9×(a·x) = x·(16 + 9·a)
When the dimensions of the initial and new arrangement are equal, we have;
10 + 12·a = 16 + 9·a
12·a - 9·a = 16 - 10 = 6
3·a = 6
a = 6 ÷ 3 = 2
a = 2
Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;
10 + 12·a < 16 + 9·a
Which gives;
x·(10 + 12·a) < x·(16 + 9·a)
Therefore;
The initial total car park space is less than the space required for 16
compact spaces and 9 full size spaces, therefore; the store owners are
incorrect.
Learn more about writing expressions here:
brainly.com/question/551090
Answer:
g(4x) = 192x^3
Step-by-step explanation:
For this problem, f(x) is irrelevant since we are simply are dealing with g(x). We will simply replace the value of x in g(x) with 4x. So let's do that.
g(x) = 3x^3
g(4x) = 3(4x)^3
g(4x) = 3(4^3)(x^3)
g(4x) = 3(64)(x^3)
g(4x) = 192x^3
Hence, g(4x) is 192x^3.
Cheers.
Yup! We're all pretty good here.
Answer:
2.5
Step-by-step explanation:
Simplifying
2y + -1.7 = 3.3
Reorder the terms:
-1.7 + 2y = 3.3
Solving
-1.7 + 2y = 3.3
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '1.7' to each side of the equation.
-1.7 + 1.7 + 2y = 3.3 + 1.7
Combine like terms: -1.7 + 1.7 = 0.0
0.0 + 2y = 3.3 + 1.7
2y = 3.3 + 1.7
Combine like terms: 3.3 + 1.7 = 5
2y = 5
Divide each side by '2'.
y = 2.5
Simplifying
y = 2.5
