Answer:
1 Use Difference of Squares:
a^2-b^2=(a+b)(a−b).
10(x^2-4^2)
2 Simplify 4^2 to 16
10(x^2 −16)
3 Expand by distributing terms.
10x^2 −160
Step-by-step explanation:
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§ALEX§
Um we need to see the diagram in order to answer this question sorry...but have a good day :)
The standard deviation of the set of values (2, 3, 6, 9, 10) is <span>square root of 12.5 (</span>

) therefore
OPTION C
Since the line of refrection is a horizontal line, the x-coordinate of the image will be the same as the x-coordinate of the point P(-1, -1). P(-1, -1) is one unit above the line y = -2, hence the image will be one unit below the line y = -2. Therefore the coordinate of the image is (-1, -3)