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Eddi Din [679]
3 years ago
12

Can u please help thank you

Mathematics
1 answer:
torisob [31]3 years ago
8 0
Answer : 6 is opposite of 1
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What are two different ways you could find the value of a? Explain these methods.
Ulleksa [173]
See the attached figure to better understand the problem

we know that

1) First way to find the value of a
in the triangle ABC
<span>applying the Pythagorean theorem
AC</span>²=AB²+BC²--------> BC²=AC²-AB²-----> BC²=25²-15²-----> BC²=625-225
BC²=400--------> BC=20 units
a=BC
a=20 units

2) Second way to find the value of a

in the triangle ABD

AB²=AD²+BD²--------> BD²=AB²-AD²-----> BD²=15²-9²---> BD²=144
BD=12 units

in the triangle BDC
a=BC
BC²=BD²+DC²-----> 12²+16²----> 144+256------> BC²=400
BC=20 units
a=20 units

4 0
4 years ago
Read 2 more answers
Which represents the domain of the following relation? {(-6, 5), (-4, 3), (-1, 0), (4, 3)}
olga2289 [7]
Domain are the x values
It would be d) -6, -4, -1, 4
7 0
3 years ago
Complete the algebra terms with table and graph given y = 2x +3
Bezzdna [24]
It’s really easy all you have to do is plug in the numbers
(In order)
-1, 1, 3, 5, 7, 9
4 0
3 years ago
Algebra help - please be so kind - god bless. 2&amp;3 please
azamat
2. -11 sq rt of 112
Sq rt of 16 times sq rt of 7
Becomes 4 sq rt of 7
Multiply -11 times 4 sq rt of 7
-44 sq rt of 7
Answer A


3. Subtract 17-9 since they are hitch the same sq rt

Answer 8 sq rt of 17
4 0
3 years ago
write the expressions for when you translate the graph of y = |x+2| a) one unit up b) one unit down c) one unit to the left d) o
irina1246 [14]

Hello!

This question is about which values you are changing when you are transforming an equation.

Let's go through the parent function for an absolute value equation and its various transformations.

y=a|b(x-c)|+d

Since we are only looking at horizontal and vertical transformations, we only need to worry about the c and d values.

The c value of a function determines a function's horizontal position, and the d value of a function determines a function's vertical position.

One thing to note here is that the c value is being subtracted from the x value, meaning that if the function is being transformed to the right, you would actually be subtracting that value, while the d value behaves like a normal value, if it is being added, the function is transformed up, and vice versa.

Now that we know this, let's write each expression.

a) y=|x+2|+1

b) y=|x+2|-1

c) y=|x+3|

d) y=|x+1|

Hope this helps!

6 0
3 years ago
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