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yarga [219]
3 years ago
8

A phone company has a monthly data plan where a customer pays flat monthly fee of $ 15 and then a certain amount of money per gi

gabyte (GB) of data used on the phone. If a customer uses 3 GB, the monthly cost will be $ 24 . If the customer uses 7 GB, the monthly cost will be $ 36.
Find a linear equation for the monthly cost of the data plan as a function of x, the number of MB used.
Mathematics
1 answer:
ololo11 [35]3 years ago
3 0

Answer:

Step-by-step explanation:

let x represent the number of MB used in a month.

Let y represent the monthly cost of using x MB.

If we plot y on the vertical axis and x on the horizontal axis, a straight line would be formed. The slope of the straight line would be

Slope, m = (36 - 24)/(7 - 3)

m = 12/4 = $3

We would represent the linear equation in the slope - intercept form which is expressed as

y = mx + c

Where

c = y intercept

m = slope

At the y intercept, x = 0. Therefore, the y intercept is the flat monthly fee of $15. It is charged whether MB is used or not. Therefore, the linear equation is

y = 3x + 15

Or

C(x) = 3x + 15

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Which value is NOT a solution of 8x3 – 1 = 0?
Tpy6a [65]

<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>

Answer:

Any value other than the values x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4} will not be a solution of 8x^3\:-\:1\:=\:0.

Step-by-step explanation:

Considering the equation

8x^3\:-\:1\:=\:0

Steps to solve the equation

8x^3-1=0

\mathrm{Add\:}1\mathrm{\:to\:both\:sides}

8x^3-1+1=0+1

\mathrm{Simplify}

x^3=\frac{1}{8}

\mathrm{Divide\:both\:sides\:by\:}8

\frac{8x^3}{8}=\frac{1}{8}

\mathrm{Simplify}

x^3=\frac{1}{8}

As

\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}

So,

x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}

Therefore,

Any value other than the values x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4} will not be a solution of 8x^3\:-\:1\:=\:0.

Keywords: solution, value

Learn more about equation solution from  brainly.com/question/1679491

#learnwithBrainly

7 0
3 years ago
Graph the line -1 passing through the point (-4,5)​
Dennis_Churaev [7]

Answer:

Step-by-step explanation:

If you want to find the equation of line with a given a slope of which goes through the point (-4,5), you can simply use the point-slope formula to find the equation:

---Point-Slope Formula---

where is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

Plug in , , and (these values are given)

Distribute  

Multiply and to get

Add -1 to both sides to isolate y

Combine like terms and to get the answer

So the equation of the line with a slope of which goes through the point (-4,5) is:

which is now in y=mx = b form where the slope is m=-4/5  and the y-intercept is b=1

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zhuklara [117]

Answer:

|9.4-1.8|

Step-by-step explanation:

To find distance, you take the largest value minus the smallest value and then take the absolute value of that because distance can't be negative.

7 0
3 years ago
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